a. Degrees of freedom and t-value b. Margin of error and confidence interval c. Based on your interval in part (b), we can state with 99 percent confidence that the average bone densities in two populations of newborns 1. In a study of maternal cigarette smoking and bone density in newborns, the followinginformation was obtainedInfants of mothers who smoked: n1 = 11, ē1 = 0.098, 81 = 0.026;%3DInfants whose mothers did not smoke: n2 = 17, 2 = 0.095, s2 = 0.025%3DWe wish to calculate a 99% confidence interval for µ1 – 42.

Name: a. Degrees of freedom and t-value b. Margin of error and confidence in
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Description: a. Degrees of freedom and t-value b. Margin of error and confidence interval c. Based on your interval in part (b), we can state with 99 percent confidence that the average bone densities in two populations of newborns 1. In a study of maternal cigar

Given : n1 = 11 n2 = 17 s1 = 0.026 s2 = 0.025 x1 = 0.098x2 = 0.095

Answered: 1. In a study of maternal cigarette…

MATLAB: An Introduction with Applications

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a. Degrees of freedom and t-value

b. Margin of error and confidence interval

c. Based on your interval in part (b), we can state with 99 percent confidence that the average bone densities in two populations of newborns

1. In a study of maternal cigarette smoking and bone density in newborns, the following
information was obtained
Infants of mothers who smoked: n1 = 11, ē1 = 0.098, 81 = 0.026;
%3D
Infants whose mothers did not smoke: n2 = 17, 2 = 0.095, s2 = 0.025
%3D
We wish to calculate a 99% confidence interval for µ1 – 42.

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