1. Imagine a positively charged particle entering a uniform electric field generated by two parallel plates, as shown below. The magnitude of the electric field is 2.5 x105 N/C, and the speed of the proton when it enters is 1.5x10' m/s. Neglect the force of gravity in this problem. a. Which force/forces is/are acting on the proton in the x and the y directions while it is between the parallel plates? What are their magnitudes and directions? b. What is the proton's final velocity in the x direction as it emerges from the parallel plates? c. By what distance, d, has the proton been deflected when it leaves the plates? Now, an electron is sent into the same field, from the left, with the same initial velocity as the proton. d. By what distance, d, has the electron been deflected when it leaves the plates? Be sure to indicate the direction. e. What would the initial speed of the electron in the x-direction need to be for it to have the same magnitude of deflection as the proton? f. Express this speed in terms of the speed of light, c = 3.0 x 10³ m/s. Comment on your result. 12.0 cm-

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I have attached (d) part please solve (e) and (f) sub-parts

please solve fast and accurate. 
thanks

a).
1.6x10¬19
x2.5x105
1.67x10-27
a =
a = 2. 39x103 m/s?
Vxi = 1. 5x107 m/s
Vyi = 0
horiznotal distace covered
L = 0. 12 m
vertical acceleration a = 2. 39x1013 m/s²
time taken for the horizontla dis tan ce
L = Vxit + at²
%3D
sin ce ax = 0
t = 0. 12/1. 5x107
t = 8x10-9
same time for the y direction as well
so V final is
d = vxit + at?
%3D
d = 0 + 2. 39x1013 (8x10-9)´d = 7. 648x10-4
m
d = 0.7648 mm
Transcribed Image Text:a). 1.6x10¬19 x2.5x105 1.67x10-27 a = a = 2. 39x103 m/s? Vxi = 1. 5x107 m/s Vyi = 0 horiznotal distace covered L = 0. 12 m vertical acceleration a = 2. 39x1013 m/s² time taken for the horizontla dis tan ce L = Vxit + at² %3D sin ce ax = 0 t = 0. 12/1. 5x107 t = 8x10-9 same time for the y direction as well so V final is d = vxit + at? %3D d = 0 + 2. 39x1013 (8x10-9)´d = 7. 648x10-4 m d = 0.7648 mm
1. Imagine a positively charged particle entering a uniform electric field
generated by two parallel plates, as shown below.
The magnitude of the electric field is 2.5 x105 N/C, and the speed of
the proton when it enters is 1.5×10' m/s.
Neglect the force of gravity in this problem.
a. Which force/forces is/are acting on the proton in the x and the y
directions while it is between the parallel plates? What are their
magnitudes and directions?
b. What is the proton's final velocity in the x direction as it emerges from
the parallel plates?
c. By what distance, d, has the proton been deflected when it leaves the
plates?
Now, an electron is sent into the same field, from the left, with the
same initial velocity as the proton.
d. By what distance, d, has the electron been deflected when it leaves the
plates? Be sure to indicate the direction.
e. What would the initial speed of the electron in the x-direction need to
be for it to have the same magnitude of deflection as the proton?
f. Express this speed in terms of the speed of light, c = 3.0 x 10% m/s.
Comment on your result.
-12.0 cm-
Transcribed Image Text:1. Imagine a positively charged particle entering a uniform electric field generated by two parallel plates, as shown below. The magnitude of the electric field is 2.5 x105 N/C, and the speed of the proton when it enters is 1.5×10' m/s. Neglect the force of gravity in this problem. a. Which force/forces is/are acting on the proton in the x and the y directions while it is between the parallel plates? What are their magnitudes and directions? b. What is the proton's final velocity in the x direction as it emerges from the parallel plates? c. By what distance, d, has the proton been deflected when it leaves the plates? Now, an electron is sent into the same field, from the left, with the same initial velocity as the proton. d. By what distance, d, has the electron been deflected when it leaves the plates? Be sure to indicate the direction. e. What would the initial speed of the electron in the x-direction need to be for it to have the same magnitude of deflection as the proton? f. Express this speed in terms of the speed of light, c = 3.0 x 10% m/s. Comment on your result. -12.0 cm-
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