1. (i) In a certain population, the force of mortality p, at age x is as follov 0.007, 61
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- Standard Ultimate Survival Model says that the force of mortality equals Ho = A+ Bc" with A = 0.00022, B = 2.7 × 10-6, c = 1.124 %3D Let the annual interest rate be į = 0.05. %3D For a life (aged 17), the present value of a benefit of $1 payable immediately on death is a random variable, Z. Find P[Z > 0.3]Let the life span of a material be given by the probability function f(x)=c²xe^(-cx) (x≥ 0). Determine the average lifetime of this material.OGiven a normal distribution with u = 30 and o = 6, find the value of x that has *70% of the normal curve area to the right
- Consider an electronic component with a lifetime denoted by a random variable T which is modelled by an exponential distribution with a parameter of average lifetime B = 5. Part A: Exponential Distribution Write the probability that a component is still working after 5 years, as an expression: P(T > 5) = | dt Use t for T e() for exponential function ()! for factorial ( )*( ) for exponents • Help entering equations Part B: Probability Write the probability that a component is still working after 5 years, numerically: P(T > 5) = • Help entering equations Part C: Binomial Distribution Let X be the random variable representing the number of components that are still working after 5 years. Write the binomial distribution for at least 3 components that are still working, as an expression: P(X 2 3) = Use p for parameter p x for the value of the random variable X e() for exponential function C(n,x) for combination of "x out of n" (O! for factorial (O*) for exponents • Help entering equations…The Table below shows the average score of the150 students sampled from the University of the East Europe in the academic year 2020/2021. Score (out of 100) Number of students 40-49 19 50-59 32 60-69 49 70-79 29 80-89 21 Given that Class Frequency 40 - 49 19 50 - 59 32 60 - 69 49 70 - 79 29 80 - 89 21 Class(1) Frequency (f)(2) Mid value (x)(3) f⋅x(4)=(2)×(3) cf(6) 40-49 19 44.5 845.5 19 50-59 32 54.5 1744 51 60-69 49 64.5 3160.5 100 70-79 29 74.5 2160.5 129 80-89 21 84.5 1774.5 150 n=150 ∑f⋅x=9685 Use your results above to comment on the shape of the distribution. Give a reason for you answer.QUESTION 2 Given the probability density function f(x)=(0.02^9 x^8*e^(-0.02x))/8! for x>0 and f(x)=0 otherwise. Determine the mean and variance of the distribution. Round the answers to the nearest integer. a) the mean b) The variance
- An accident-prone motorist has two tragic accidents with two weeks between rooms. The 'waiting time' (measured in days) between two accidents can be approximately approximated as exponentially distributed with unknown expected value µ. Determine a 90% condensation interval for µ. Please explin so I understand to ba able to solve similar kind of questions..he distribution of the number of imperfections per 10 meters of synthetic fabric is given by the following function, If cost of this defect is given by the following equation g(x)-1/100 (x^2+2x+10), what is the ?expected cost 2 3 4. f(x) 0.41 0.37 0.16 0.05 0.01Let x luck indicate a lognormal distribution with u = 1, a ^ 2 = 1 parameter. So WHAT IS PROBABILITY P (X> 10)? a. 0097 b.084 c.none of them d.0.134 e.0.113