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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. pe (1– p)e00 20 (1– p)e“ -0.2 (A) pe 100 10,000 100 10,000 pe (1- p)e 00 -20 pe 100 (1– p)e02 -0.2 (B) 100 10,000 10,000 pe (1– p)e01 pe 20 (1– p)e-02 -0.01 (C) 100 10,000 100 10,000 (1– p)e -0.01 (1– p)e02 pe -20 pe 100 (D) 100 10,000 10,000 e-0.01 +(1–, (E) e20 p. 100 10,000 100 10,000

Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. pe (1– p)e00 20 (1– p)e“ -0.2 (A) pe 100 10,000 100 10,000 pe (1- p)e 00 -20 pe 100 (1– p)e02 -0.2 (B) 100 10,000 10,000 pe (1– p)e01 pe 20 (1– p)e-02 -0.01 (C) 100 10,000 100 10,000 (1– p)e -0.01 (1– p)e02 pe -20 pe 100 (D) 100 10,000 10,000 e-0.01 +(1–, (E) e20 p. 100 10,000 100 10,000

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. pe' (1– p)e00 20 (1– p)e“ -0.2 (A) ре 100 10,000 100 10,000 pe (1– p)e00 -20 (1– p)e0² 0.2 (B) pe 100 10,000 100 10,000 pe (1– p)e01 -0.01 Pe20 100 (C) (1– p)e-02 100 10,000 10,000 pe . (1– p)e-0 -0.01 -20 (D) pe + (1– p)e-02 100 10,000 100 10,000 el p. 100 10,000 e-0.01 (E) +(1– e20 100 10,000
Transcribed Image Text:Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. pe' (1– p)e00 20 (1– p)e“ -0.2 (A) ре 100 10,000 100 10,000 pe (1– p)e00 -20 (1– p)e0² 0.2 (B) pe 100 10,000 100 10,000 pe (1– p)e01 -0.01 Pe20 100 (C) (1– p)e-02 100 10,000 10,000 pe . (1– p)e-0 -0.01 -20 (D) pe + (1– p)e-02 100 10,000 100 10,000 el p. 100 10,000 e-0.01 (E) +(1– e20 100 10,000
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