1. How many grams of oxygen can be formed if 295.0 g KCIO3 react? Show all required calculations and report the answer with the correct significant figures. 2KCIO3 2KCI + 3O2
1. How many grams of oxygen can be formed if 295.0 g KCIO3 react? Show all required calculations and report the answer with the correct significant figures. 2KCIO3 2KCI + 3O2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
1. How many grams of oxygen can be formed if 295.0 g of KClO₃ react? Show all required calculations and report the answer with the correct significant figures.
**Chemical Reaction:**
\[ 2 \text{KClO}_3 \rightarrow 2 \text{KCl} + 3 \text{O}_2 \]
**Explanation:**
To calculate the grams of oxygen produced, follow these steps:
1. **Determine the molar mass of KClO₃:**
- Potassium (K): 39.1 g/mol
- Chlorine (Cl): 35.5 g/mol
- Oxygen (O): 16.0 g/mol
- Molar mass of KClO₃ = 39.1 + 35.5 + (3 × 16.0) = 122.5 g/mol
2. **Calculate moles of KClO₃ in 295.0 g:**
\[
\text{Moles of KClO}_3 = \frac{295.0 \, \text{g}}{122.5 \, \text{g/mol}} = 2.41 \, \text{mol}
\]
3. **Use stoichiometry to find moles of O₂ produced:**
- From the reaction, 2 moles of KClO₃ produce 3 moles of O₂.
- So, 2.41 moles of KClO₃ will produce:
\[
\left(\frac{3}{2}\right) \times 2.41 = 3.62 \, \text{mol of O}_2
\]
4. **Calculate the mass of O₂:**
- Molar mass of O₂ = 32.0 g/mol
\[
\text{Mass of O}_2 = 3.62 \, \text{mol} \times 32.0 \, \text{g/mol} = 116.0 \, \text{g}
\]
5. **Result:**
- The mass of oxygen formed is 116.0 g, reported with the correct significant figures.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffccae16d-a3f5-4ed1-bb18-084e96e3fc22%2F8545cfdb-e039-4c16-8a2b-8cc2cebde4b2%2Farr9pag_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
1. How many grams of oxygen can be formed if 295.0 g of KClO₃ react? Show all required calculations and report the answer with the correct significant figures.
**Chemical Reaction:**
\[ 2 \text{KClO}_3 \rightarrow 2 \text{KCl} + 3 \text{O}_2 \]
**Explanation:**
To calculate the grams of oxygen produced, follow these steps:
1. **Determine the molar mass of KClO₃:**
- Potassium (K): 39.1 g/mol
- Chlorine (Cl): 35.5 g/mol
- Oxygen (O): 16.0 g/mol
- Molar mass of KClO₃ = 39.1 + 35.5 + (3 × 16.0) = 122.5 g/mol
2. **Calculate moles of KClO₃ in 295.0 g:**
\[
\text{Moles of KClO}_3 = \frac{295.0 \, \text{g}}{122.5 \, \text{g/mol}} = 2.41 \, \text{mol}
\]
3. **Use stoichiometry to find moles of O₂ produced:**
- From the reaction, 2 moles of KClO₃ produce 3 moles of O₂.
- So, 2.41 moles of KClO₃ will produce:
\[
\left(\frac{3}{2}\right) \times 2.41 = 3.62 \, \text{mol of O}_2
\]
4. **Calculate the mass of O₂:**
- Molar mass of O₂ = 32.0 g/mol
\[
\text{Mass of O}_2 = 3.62 \, \text{mol} \times 32.0 \, \text{g/mol} = 116.0 \, \text{g}
\]
5. **Result:**
- The mass of oxygen formed is 116.0 g, reported with the correct significant figures.
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