1. How many grams of oxygen can be formed if 295.0 g KCIO3 react? Show all required calculations and report the answer with the correct significant figures. 2KCIO3 2KCI + 3O2

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**Problem Statement:**

1. How many grams of oxygen can be formed if 295.0 g of KClO₃ react? Show all required calculations and report the answer with the correct significant figures.

**Chemical Reaction:**

\[ 2 \text{KClO}_3 \rightarrow 2 \text{KCl} + 3 \text{O}_2 \]  

**Explanation:**

To calculate the grams of oxygen produced, follow these steps:

1. **Determine the molar mass of KClO₃:**
   - Potassium (K): 39.1 g/mol
   - Chlorine (Cl): 35.5 g/mol
   - Oxygen (O): 16.0 g/mol 
   - Molar mass of KClO₃ = 39.1 + 35.5 + (3 × 16.0) = 122.5 g/mol

2. **Calculate moles of KClO₃ in 295.0 g:**
   \[
   \text{Moles of KClO}_3 = \frac{295.0 \, \text{g}}{122.5 \, \text{g/mol}} = 2.41 \, \text{mol}
   \]

3. **Use stoichiometry to find moles of O₂ produced:**
   - From the reaction, 2 moles of KClO₃ produce 3 moles of O₂.
   - So, 2.41 moles of KClO₃ will produce:
   \[
   \left(\frac{3}{2}\right) \times 2.41 = 3.62 \, \text{mol of O}_2
   \]

4. **Calculate the mass of O₂:**
   - Molar mass of O₂ = 32.0 g/mol
   \[
   \text{Mass of O}_2 = 3.62 \, \text{mol} \times 32.0 \, \text{g/mol} = 116.0 \, \text{g}
   \]

5. **Result:**
   - The mass of oxygen formed is 116.0 g, reported with the correct significant figures.
Transcribed Image Text:**Problem Statement:** 1. How many grams of oxygen can be formed if 295.0 g of KClO₃ react? Show all required calculations and report the answer with the correct significant figures. **Chemical Reaction:** \[ 2 \text{KClO}_3 \rightarrow 2 \text{KCl} + 3 \text{O}_2 \] **Explanation:** To calculate the grams of oxygen produced, follow these steps: 1. **Determine the molar mass of KClO₃:** - Potassium (K): 39.1 g/mol - Chlorine (Cl): 35.5 g/mol - Oxygen (O): 16.0 g/mol - Molar mass of KClO₃ = 39.1 + 35.5 + (3 × 16.0) = 122.5 g/mol 2. **Calculate moles of KClO₃ in 295.0 g:** \[ \text{Moles of KClO}_3 = \frac{295.0 \, \text{g}}{122.5 \, \text{g/mol}} = 2.41 \, \text{mol} \] 3. **Use stoichiometry to find moles of O₂ produced:** - From the reaction, 2 moles of KClO₃ produce 3 moles of O₂. - So, 2.41 moles of KClO₃ will produce: \[ \left(\frac{3}{2}\right) \times 2.41 = 3.62 \, \text{mol of O}_2 \] 4. **Calculate the mass of O₂:** - Molar mass of O₂ = 32.0 g/mol \[ \text{Mass of O}_2 = 3.62 \, \text{mol} \times 32.0 \, \text{g/mol} = 116.0 \, \text{g} \] 5. **Result:** - The mass of oxygen formed is 116.0 g, reported with the correct significant figures.
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