1. How long it takes to deposit 20.4 grams of gold (197 g/mol) when 5.6 ampere current was passed through its Au*3 aqueous solution? Au* (aq) + 3e → Au(s) F = 9.65 x 104 Coulombs/moles of es

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1. How long it takes to deposit 20.4 grams of gold (197 g/mol) when 5.6 ampere current was passed
(aq) + 3e → Au(s)
through its Au*3 aqueous solution? Au*3
F = 9.65 x 104 Coulombs/moles of
es
2. Use the following information, calculate the molar mass of metal “X" and use the periodic table to
identify the metal: When 1.24 amps current passed thru it's XCI aqueous solution for 1.5 hours,
5.93 grams of metal X was deposited. {keep in mind the CI-1 has -1 charge and molar mass of XCI =
mass/number of moles so first calculate the mass then molar mass}
Transcribed Image Text:1. How long it takes to deposit 20.4 grams of gold (197 g/mol) when 5.6 ampere current was passed (aq) + 3e → Au(s) through its Au*3 aqueous solution? Au*3 F = 9.65 x 104 Coulombs/moles of es 2. Use the following information, calculate the molar mass of metal “X" and use the periodic table to identify the metal: When 1.24 amps current passed thru it's XCI aqueous solution for 1.5 hours, 5.93 grams of metal X was deposited. {keep in mind the CI-1 has -1 charge and molar mass of XCI = mass/number of moles so first calculate the mass then molar mass}
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