Please answer all. Circle the best answer for each of the questions.1. Given the following reaction, identify the species that is oxidized.5CO + 1205 + 2 + 5CO2а. СОb. 1205с. 12d. CO2e. Nothing is reduced in the reaction.2. When the potential a half reaction was measured against a Ag |AgCl reference electrode, thepotential was found to be -0.548 V. What would the potential when the same half reaction wasmeasured against a S.C.E. reference electrode?а. —0.592 Vb. 0.592 Vc. -0.351 Vd. 0.504 Vе. —0.504 V3. When using EDTA to determine metal ion concentration in a solution, what is the best way toovercome a slow equilibrium between the metal ion analyte and EDTA?a. Use a masking agent.b. Use an auxiliary complexing agent.Perform a displacement titration.с.d. Perform an indirect titration.e. Perform a back titration.

Answered: 1. Given the following reaction,…

1. Given the following reaction, identify the species that is oxidized. 5CO + 1205 s 2 + 5CO2 а. СО b. 1205 с. 12 d. CO2 e. Nothing is reduced in the reaction.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72
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