1. Given the following dennition of fun, what will be output by the call funi (4): void fun1(int n) { int i=0; * * } **** * if (n> 1) { * fun1(n-1); + } for (i = 0; i
1. Given the following dennition of fun, what will be output by the call funi (4): void fun1(int n) { int i=0; * * } **** * if (n> 1) { * fun1(n-1); + } for (i = 0; i
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![1. Given the following definition of fun1, what will be output by the call fun1 (4)?
void fun1(int n) {
int i = 0;
if (n > 1) {
O O
* *
*
* *
★
*
*
* * *
*
*
*
*
*
*
fun1(n-1);
}
for (i = 0; i<n; i++) {
cout << "*";
}
cout << endl;
}
*
* *
* *
* * * *
* *
* *
* *
* * *
* * *](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccc4b4bb-a94d-4dc4-be7d-92733a14ab19%2Fee244ca8-67e4-44a5-b49b-16e851a0870e%2Fgtnsaof_processed.png&w=3840&q=75)
Transcribed Image Text:1. Given the following definition of fun1, what will be output by the call fun1 (4)?
void fun1(int n) {
int i = 0;
if (n > 1) {
O O
* *
*
* *
★
*
*
* * *
*
*
*
*
*
*
fun1(n-1);
}
for (i = 0; i<n; i++) {
cout << "*";
}
cout << endl;
}
*
* *
* *
* * * *
* *
* *
* *
* * *
* * *
![A member variable declared in the private section of a base class can be directly accessed within a member function of a derived class that inherits from this base class.
True
False](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccc4b4bb-a94d-4dc4-be7d-92733a14ab19%2Fee244ca8-67e4-44a5-b49b-16e851a0870e%2Frv5ejgg_processed.png&w=3840&q=75)
Transcribed Image Text:A member variable declared in the private section of a base class can be directly accessed within a member function of a derived class that inherits from this base class.
True
False
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