1. From the field notes of a closed traverse show below, adjust the traverse. LINES BEARING DISTANCES АВ Due North 400 + 1 ВС N 45° E 800 CD S 60° E 700 DE S 200 W 600 EA S 86° 59' W 966.34 a. Solve for the Latitude and Departure b. Solve for the Adjusted and Balanced Departure and Latitude using compass/transit rule (specit your choice) c. Solve for the Balanced Length and Bearing d. Using the adjusted departure and latitude, calculate the area of the traverses using DMD/DPD method. (Specify your choice)

1. From the field notes of a closed traverse show below, adjust the traverse. LINES BEARING DISTANCES АВ Due North 400 + 1 ВС N 45° E 800 CD S 60° E 700 DE S 200 W 600 EA S 86° 59' W 966.34 a. Solve for the Latitude and Departure b. Solve for the Adjusted and Balanced Departure and Latitude using compass/transit rule (specit your choice) c. Solve for the Balanced Length and Bearing d. Using the adjusted departure and latitude, calculate the area of the traverses using DMD/DPD method. (Specify your choice)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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a.) Plot the traverse in the figure. Use appropriate scale and label the traverse. b.) Adjust the traverse in the figure using compass rule
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1. Given the following data of a closed traverse: a. use sine law to determine the distance of line 3-4 b. use sine law to determine the distance of line 4-5
Q2/B- A rough sketch of the situation is shown in Fig. PABCQP is a closed traverse. Lengths of lines CQ and QP are to be determined. Compute the latitudes and departures as shown in the table. Assume that the length of CQ = L1 and that of QP =L2. Line 12888 PA AB BC CQ QP Length 150 500 300 L₁ L₂ Bearing N10° 15'E N32° 45'E N65° 30'E $50° 30'E S68° 45'W Latitude 147.6 420.52 124.41 0.6361L₁ 0.3624L₂ Departure 26.69 270.49 272.99 0.77164₁ 0.932L₂
A traverse has the following data: LINE LENGTH BEARING АВ 33.48 N 73°23' E BC 8.11 S 39°30' E CD 39.42 S 43°40' W DE 7.08 N 39°50' W EA 22.02 N 17°33' W Use compass rule in adjusting the closed traverse and compute for the Linear Error of Closure and Relative Error of Closure.
Need help with question 9 only please
A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m/ N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W By adjusting the traverse using Compass Rule, 1. Find the latitude correction for line AB. A. 0.489 m B. 0.905 m C. 0.550 m D. 0.109 m 2. Find the corrected departure of line BC. A. 40.114 m B. 39.118 m C. 40.512 m D. 39.931 m
#2 only - please answer correctly
provide answers and solutions to letters G and H
Can all he work be done in detail please
With the same problem, what would be the sketch of this data?