1. For the charging process, show that if I-lo exp(-t/ta), then In (lo/1) (1/TR) t.
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Q: QUESTION 4 Find the acceleration in Pm/s² (1P = 1015) for the electron in problem 22.48.a. using a…
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- I;m not sure how to fix this answer, it will not allow 10^3.2) a) Which physical law is the basis for the continuity equation? b) Write continuity equation in differential form. c) Write two equations that each stand for magnetostatic case. d) An agglomeration of protons, that we shall treat as a point, explodes. 10 protons per second fly in all directions on average. What is the sign of div ?⃗(?⃗) at the position of the agglomerate? e) Write out div ?⃗(����⃗). Hint: remember what a delta function does to a volume integral.A Hall probe calibrated to read 1.00 µV when placed in a 1.84 T field is placed in a 0.135 T field. What is its output voltage? Thanks!
- The resirtor R power, tnハう üsms Hirchuffis fules, deternine the value of R, CThere are 2 pusrible vulues)F=0.8975r^-2.00 And re-writing it as: (4)F=0.8975/r^-2.00 We can now compare it with Coulomb’s equation: (1)F=K|q1q2|/r^2 So, comparing these equations (4) and (1) we realize that: k=|q1q2|=0.8975 Plugging in values for charges: q1 = -10µC, and q2 = 10µC, isolating k (Coulomb’s constant), and recalling that 1µC = 10-6 C, we get: k|-10µC*10µC|=0.8975 k=0.8934/|-10µC*10µC|= 0.8934/10*10^-6C*10*10^-6C (3) Use this Example calculation above, and the trendline equation (3) coefficients that you have obtained on your graph, to find k. Show your work below. Be careful with powers of ten. k= 0.8975/|-10µC*10µC|= 0.8975/10*10^-6C*10*10^-6C = (5) Now, important part in reporting the answer is properly showing its units. To derive the SI units for Coulomb’s constant k, let’s look again at the equation (1), and re-write it as: k=F*r^2/|q1q2| (6) Recalling the units for all parameters in this equation: Force, F – Newtons, [N] Distance, r –…