1. For example, a sample known to contain 60.05% chlorine as chloride was assayed for chlorine, and the following values were obtained: 57.63, 57.68, 57.66 and 57.63. It is obvious from the close agreement between the individual values and the mean value that the indeterminate error of the analysis is very small, or the precision of the measurement is high. Comparing the mean value obtained in the analysis with the true value (60.05) and observing the absolute error calculated.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Compute for the following problems stated below. Upload your computation for each problem. Express
your final answer into 4 decimal places except for RSD which is 2 decimal places. Encircle your final
answer. Compute for the following parameters:
d. RSD
e. Absolute Error
f. % Relative Error
1. For example, a sample known to contain 60.05% chlorine as chloride was assayed for chlorine, and
the following values were obtained: 57.63, 57.68, 57.66 and 57.63. It is obvious from the close
agreement between the individual values and the mean value that the indeterminate error of the
analysis is very small, or the precision of the measurement is high. Comparing the mean value
obtained in the analysis with the true value (60.05) and observing the absolute error calculated.
Transcribed Image Text:Compute for the following problems stated below. Upload your computation for each problem. Express your final answer into 4 decimal places except for RSD which is 2 decimal places. Encircle your final answer. Compute for the following parameters: d. RSD e. Absolute Error f. % Relative Error 1. For example, a sample known to contain 60.05% chlorine as chloride was assayed for chlorine, and the following values were obtained: 57.63, 57.68, 57.66 and 57.63. It is obvious from the close agreement between the individual values and the mean value that the indeterminate error of the analysis is very small, or the precision of the measurement is high. Comparing the mean value obtained in the analysis with the true value (60.05) and observing the absolute error calculated.
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