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1. Fischl, a scientist from Mondstadt specializing in electrochemistry, performed an electrolytic cell experiment on an unknown metal solution. She was able to deposit 9.701 g of the metal as solid on the cathode after applying a 1.500 A current for 10.00 hours. Her assistant, Oz, had previously noted that 3 electrons are involved per mole of the metal deposited. a. Determine the molar mass of the unknown metal in g/mol. g/mol b. What is the identity of the unknown metal? Mn Cd Cr ipts of the compounds or ions, the text formatting is Sr given as follows: Cd2+ = Cd^2+ Cu2+ = Cu^2+ 2. In another experiment, Fischl used cadmium metal to form an electrode she can use for her voltaic cell. She wanted to determine the electric potential produced by the cadmium electrode (and 1.0 M of its corresponding electrolyte solution) with a Copper electrode in 0.10 M CuSO4 solution at 25 °C. Predict the following: a. OHR of the voltaic cell: Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V | cd(s) – Cd^2+(aq)+ 2e-, Eo = + 0.40 V b. RHR of the voltaic cell: Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V c. Number of electrons involved in the redox reaction (n): d. Overall reaction for the voltaic cell: e. Standard cell potential, E°cel: V f. Theoretical Ecell : g. If the measured Ecell Was 0.50 V, calculate the percent error. %

1. Fischl, a scientist from Mondstadt specializing in electrochemistry, performed an electrolytic cell experiment on an unknown metal solution. She was able to deposit 9.701 g of the metal as solid on the cathode after applying a 1.500 A current for 10.00 hours. Her assistant, Oz, had previously noted that 3 electrons are involved per mole of the metal deposited. a. Determine the molar mass of the unknown metal in g/mol. g/mol b. What is the identity of the unknown metal? Mn Cd Cr ipts of the compounds or ions, the text formatting is Sr given as follows: Cd2+ = Cd^2+ Cu2+ = Cu^2+ 2. In another experiment, Fischl used cadmium metal to form an electrode she can use for her voltaic cell. She wanted to determine the electric potential produced by the cadmium electrode (and 1.0 M of its corresponding electrolyte solution) with a Copper electrode in 0.10 M CuSO4 solution at 25 °C. Predict the following: a. OHR of the voltaic cell: Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V | cd(s) – Cd^2+(aq)+ 2e-, Eo = + 0.40 V b. RHR of the voltaic cell: Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V c. Number of electrons involved in the redox reaction (n): d. Overall reaction for the voltaic cell: e. Standard cell potential, E°cel: V f. Theoretical Ecell : g. If the measured Ecell Was 0.50 V, calculate the percent error. %

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ISBN:9781305957404
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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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VOLTAIC CELL AND ELECTROLYSIS 1. Fischl, a scientist from Mondstadt specializing in electrochemistry, performed an electrolytic cell experiment on an unknown metal solution. She was able to deposit 9.701 g of the metal as solid on the cathode after applying a 1.500 A current for 10.00 hours. Her assistant, Oz, had previously noted that 3 electrons are involved per mole of the metal deposited. a. Determine the molar mass of the unknown metal in g/mol. g/mol b. What is the identity of the unknown metal? Mn Cd | Cr ipts of the compounds or ions, the text formatting is Sr given as follows: Cd2+ = Cd^2+ Cu2+ = Cu^2+ 2. In another experiment, Fischl used cadmium metal to form an electrode she can use for her voltaic cell. She wanted to determine the electric potential produced by the cadmium electrode (and 1.0 M of its corresponding electrolyte solution) with a Copper electrode in 0.10 M CuSO4 solution at 25 °C. Predict the following: a. OHR of the voltaic cell: Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V b. RHR of the voltaic cell: Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V c. Number of electrons involved in the redox reaction (n): d. Overall reaction for the voltaic cell: e. Standard cell potential, E°cell: V f. Theoretical Ecell : V g. If the measured Ecell was 0.50 V, calculate the percent error.
Transcribed Image Text:VOLTAIC CELL AND ELECTROLYSIS 1. Fischl, a scientist from Mondstadt specializing in electrochemistry, performed an electrolytic cell experiment on an unknown metal solution. She was able to deposit 9.701 g of the metal as solid on the cathode after applying a 1.500 A current for 10.00 hours. Her assistant, Oz, had previously noted that 3 electrons are involved per mole of the metal deposited. a. Determine the molar mass of the unknown metal in g/mol. g/mol b. What is the identity of the unknown metal? Mn Cd | Cr ipts of the compounds or ions, the text formatting is Sr given as follows: Cd2+ = Cd^2+ Cu2+ = Cu^2+ 2. In another experiment, Fischl used cadmium metal to form an electrode she can use for her voltaic cell. She wanted to determine the electric potential produced by the cadmium electrode (and 1.0 M of its corresponding electrolyte solution) with a Copper electrode in 0.10 M CuSO4 solution at 25 °C. Predict the following: a. OHR of the voltaic cell: Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V b. RHR of the voltaic cell: Cu(s) → Cu^2+(aq)+ 2e-, Eo = - 0.34 V Cd^2+(aq)+ 2e- → Cd(s), Eo = - 0.40 V Cu^2+(aq) + 2e- → Cu(s), Eo = + 0.34 V Cd(s) → Cd^2+(aq)+ 2e-, Eo = + 0.40 V c. Number of electrons involved in the redox reaction (n): d. Overall reaction for the voltaic cell: e. Standard cell potential, E°cell: V f. Theoretical Ecell : V g. If the measured Ecell was 0.50 V, calculate the percent error.
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