College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement**
Please answer the following question(s):
1. Find the work done in the figure below. The magnitude of \( F = 48 \, \text{N} \).
The displacement is \( \mathbf{d} = -3 \, \mathbf{i} \) and \( \theta = 120^\circ \).
**Diagram Explanation**
The diagram consists of a Cartesian coordinate system with the x and y axes. A vector \( F \) is shown in red, emanating from the origin and forming an angle \( \theta \) with the negative x-axis. The angle \( \theta \) is marked as \( 120^\circ \).
The displacement vector \( \mathbf{d} \) is along the negative x-axis with a magnitude of \(-3 \, \text{m}\).
**Work Calculation Block**
\( W = \) [ Input Box with J indicating Joules ]
**Diagram Key Information:**
- \( F = 48 \, \text{N} \)
- \( \theta = 120^\circ \)
- \( \mathbf{d} = -3 \, \mathbf{i} \)
**Work Calculation Formula:**
The work done \( W \) by a force in moving an object with a displacement is given by the formula:
\[
W = F \cdot d \cdot \cos(\theta)
\]
Where:
- \( F \) is the magnitude of the force,
- \( d \) is the magnitude of the displacement,
- \( \theta \) is the angle between the force and the displacement vector.
Plug in the values provided to solve for the work done.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F119fd9ee-0d86-405f-8fbb-1cd17cdf6dea%2F14aeadef-9d1e-4a5a-820e-109935801a70%2F72f5ey_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement**
Please answer the following question(s):
1. Find the work done in the figure below. The magnitude of \( F = 48 \, \text{N} \).
The displacement is \( \mathbf{d} = -3 \, \mathbf{i} \) and \( \theta = 120^\circ \).
**Diagram Explanation**
The diagram consists of a Cartesian coordinate system with the x and y axes. A vector \( F \) is shown in red, emanating from the origin and forming an angle \( \theta \) with the negative x-axis. The angle \( \theta \) is marked as \( 120^\circ \).
The displacement vector \( \mathbf{d} \) is along the negative x-axis with a magnitude of \(-3 \, \text{m}\).
**Work Calculation Block**
\( W = \) [ Input Box with J indicating Joules ]
**Diagram Key Information:**
- \( F = 48 \, \text{N} \)
- \( \theta = 120^\circ \)
- \( \mathbf{d} = -3 \, \mathbf{i} \)
**Work Calculation Formula:**
The work done \( W \) by a force in moving an object with a displacement is given by the formula:
\[
W = F \cdot d \cdot \cos(\theta)
\]
Where:
- \( F \) is the magnitude of the force,
- \( d \) is the magnitude of the displacement,
- \( \theta \) is the angle between the force and the displacement vector.
Plug in the values provided to solve for the work done.
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