1. Find the inverse of A =11 2 31OTE1210using the Gauss-Jordan method.

Answered: 1. Find the inverse of A = 1 1 0 1] 1 2…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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For the following matrices A, Computo AT. If A is a 2x2 matrix with real, different eigenvalues, draw the phase portraits. a) A₂= /-1.8 -0.8° a) A= ( -1.2 -0.2
I only need help with problem 2.d. Thank you.
1. Find all the cofactors of the matrix A and use it to find the inverse of A. [1] If b = |2|, and Ax=b, solve for x. (Hint: if A is invertible, Ax=b have a unique solution x=A*b) L3] 1 1 A = 1 2 3 -1 -1 -2 2 3 A = |0 1 [2 2 2
1. Define the operator K as K : f – 4f³ + f² – f given f(x) = e-2x 2. Solve (D3 + 4D² + 5D + 2)(f) = 0. 3. Solve (D3 + 2D² – D – 2)(f) = 0. - 4. Consider the general solution of number 3. Find a solution µ(x) that will satisfy the following initial condition: µ(0) = 1 Du(0) = 2 D²µ(0) = -1
Find det(A). No cofactor expansions are required. 0 0 o 15 -1 0 0 A = 21 13 1 0 4 8 23 4 3 Explain your answer. Since A is triangular, det(A) = (4)(-1)(1)(3) = -12, the product along the diagonal. Since A is triangular, det(A) = 3, the last entry in the matrix. Since A has 2 rows or 2 columns which are identical, det(A) = 0. Since A is triangular, det(A) = 4 + (-1) + 1+ 3 = 7, the sum along the diagonal. Since A has a row or column which contains all zeros, det(A) = 0.
. Derive the Adams-Bashforth Three step method by the following method. Set Yti+1 = Yt, + ah f(t;, Yt,) + bhf(t;-1, Yt,–1) + chf(t;-2, Yt;-2) (3) y expanding yt41; f(t;-2, Yt;-2) and f(t;-1, Yt;-1) in Taylor series about (t;, Yt;) and equate he coefficients of h, h² and h³ to obtain a, b and c.
2.4 Show that (AB)T + AT BT if given the following matrices. [2 1 -1] 0 -1] A = 0 1 1 -2 L4 0 1 3 [1 3 and B 2 2 Lo
need some assistancw ith 5.2.7 for expodentials and Lye Algebra attached, Thanks so much for explaining
obtain just a particular solution (the general solution can alwaysbe obtained easily by adding an arbitrary multiple of a solution of the associated homogeneous equation). In these exercises, the forcing function is an elementary sinusoidal function. If the forcing function is cos 5t, then a particular solution of the form A cos 5t will not work. However, a linear combination of cos 5t and sin 5t will work. Thus, the form for xp is A cos 5t + B sin 5t, where the constants A and B are determined by substituting the assumed form of the particular solution into the differential equation for x. In Exercises 47–52, the forcing function has severaldifferent terms. Use a form for xp consisting of the sum of the forms for each term.

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1. Find the inverse of A = 1 1 0 1] 1 2 3 1 1 using the Gauss-Jordan method.