Answer by (True) or (False) Only: 1. The next iterative value of the root of (X²– 4 = 0) using the Newton-Raphson method, if the initial guess is (3), is (2.166).

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Answer by (True) or (False) Only:
1. The next iterative value of the root of (X²– 4 = 0) using the Newton-Raphson method, if the initial guess
is (3), is (2.166).
2. In the Gauss elimination method, the given system is transformed into an equivalent system with lower
- triangular matrix.
3. The 1s' positive root of equation (tanx – 2tanhx= 0) occurs in the interval [0,1].
4. The process of finding the value of (x), corresponding to a given (y) which is not in the table, is called
" Inverse Interpolation ".
5. In bisection method if root lies between (a) and (b), then f (a) × f (b) is < 0.
Transcribed Image Text:Answer by (True) or (False) Only: 1. The next iterative value of the root of (X²– 4 = 0) using the Newton-Raphson method, if the initial guess is (3), is (2.166). 2. In the Gauss elimination method, the given system is transformed into an equivalent system with lower - triangular matrix. 3. The 1s' positive root of equation (tanx – 2tanhx= 0) occurs in the interval [0,1]. 4. The process of finding the value of (x), corresponding to a given (y) which is not in the table, is called " Inverse Interpolation ". 5. In bisection method if root lies between (a) and (b), then f (a) × f (b) is < 0.
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