1. Find the charge stored in a capacitor with a capacitance of 43.5 µF and a potential difference of 7.3V.
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Q: 17. 1/4 points| Previous Answers SerCP11 16.5.P.033.MI. points 1Previous Answers SercP11 16.5 P.033…
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A: Given data- Capacitor c1= 2.3 uF , c2=7.7 uF Battery V= 9.5 V
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- 10) Each plate of an ideal air-filled parallel-plate capacitor has an area of 0.0070 m2, and the separation of the plates is 0.070 mm. An electric field of 5.5 x 106 V/m is present between the plates. What is the capacitance of this capacitor? A) 1500 pF B) 1800 pF C) 1200 pF D) 890 pF E) 590 pF67. A 500 µF capacitor is charged at the steady rate of 100 μC/s. How long will it take to raise the potential difference between the plates of the capacitor to 10 V? (a) 5 s (b) 10 s (c) 50 s (d) 100 s2) Solve the following values in the given figure 2.0. a) Total Capacitance, Ct. b) Total Charge, Qt. FIGURE 2.0 C, IT C2 C3 A В 0.1uF 0.2uF 0.3uF Vci Vc2 Vc3 VAB = 12V
- 1. Two capacitors, C, = 5.0 µF and C, = 12.0 µF are connected in parallel to a 9.0 V battery. Find (a) the total capacitance and (b) the potential difference across each capacitor.An air capacitor, 5.80 uF, and a parallel plate is charged to a potential difference of 4.00x102 V and has a plate separation of 5.00 mm. Calculate the energy density in the region between the plates. A. u= 28.333mJ/m^3 B. u = 18.333mJ/m^3 C. u= 38.333mJ/m^3 D. u= 48.333mJ/m^32 do only a) and b) parts of this question.
- 6A parallel‑plate capacitor has a capacitance of 20 µF. What potential difference across the plates is required to store 7.2 ´ 10-4 C on this capacitor? Make a solution. 36 V 2.2 ´ 10-2 V 1.4 ´ 10-8 V 68 V16.8 An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.45 mm. If a 17.9-V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates(b) the capacitance(c) the charge on each plate