1. Find the AH° of the following reaction,CH,(9) +02(9)CO(g) + 2H2(g)Using the following data:CHA(g)+ 202(g) CO2(g) + 2H,0(g)CH (g) + CO2(g) 2C0(g) + 2H2(g)AH° = -802 kJ%3DAH° = +247 k]%3DCH (g)+ H20(g)CO(g) + 3H2(g)AH° = +206 kJ%3D

Given: CH4(g)+2O2(g)→CO2(g)+2H2O(g) ∆H°=-802 kJCH4(g)+CO2(g)→2CO(g)+2H2(g)…

Answered: 1. Find the AH° of the following…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Calculate the enthalpy change for the reaction and the type of reaction: P406(s) + 2 02(g)-----> P4010(s) Given the following enthalpies of the reaction: P4(s) + 3 02(g)------ > P40 6 (s) AH = -1640.1 kj P4(s) + 5 O2(g)----->P40 10(s) AH = -2940.1 kj
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1. Find the AH° of the following reaction, 1 CH,(2) + =0-(9) – CO(g) + 2H2(g) - Using the following data: CH,(g) + 202(g)- CO2(g) + 2H20(g) AH° = -802 k] CH (g) + CO2(g)- 2C0(g) +2H2(g) AH° = +247 kJ - CH (g)+ H20(g) CO(g) + 3H2(g) ΔΗ° = +206 k %3D