Maclaurin series.Hi, I need help to understand about the maclaurin series T_TI need to find the first four terms of e^x -1-x/x^2and I already did, but the thing is, I'm stuck when I have to do f(0), f'(0),f"(0) and so on. As attached in the picture, how am I supposed to get 1/2 when f(x)=e^x -1-x/x^2 where x=0, wouldn't it be 0????? -x + et – 1f( (x) = f (x) =x2Evaluate the function at the pointt f (0) =2-1. Find the 1st derivative:f(1) (x) = (f®) (x2) =-x + eª .xet + x – 2e* + 2-(0):(steps can be seenhere).holhow>1Evaluate the 1st derivative at the given point (f (0))'2.Find the 2nd derivative:gle) (#) = (f) (=)"'xet + x – 2e + 2x² e4xe"2х + 6е" — 6---x3x4(steps can be seen here).1Evaluate the 2nd derivative at the given point: (f (0))"12

Here given function fx=-x+ex-1x2 Use the expansion as ex=1+x+x22!+x33!+..... Thus…

Answered: 1. Find the 1st derivative: g) (2) =…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Maclaurin series.

Hi, I need help to understand about the maclaurin series T_T

I need to find the first four terms of e^x -1-x/x^2

and I already did, but the thing is, I'm stuck when I have to do f(0), f'(0),f"(0) and so on. As attached in the picture, how am I supposed to get 1/2 when f(x)=e^x -1-x/x^2 where x=0, wouldn't it be 0?????

-x + et – 1
f( (x) = f (x) =
x2
Evaluate the function at the pointt f (0) =
2
-
1. Find the 1st derivative:
f(1) (x) = (f®) (x
2) =
-x + eª .
xet + x – 2e* + 2
-
(0):
(steps can be seen
here).
hol
how>
1
Evaluate the 1st derivative at the given point (f (0))'
2.
Find the 2nd derivative:
gle) (#) = (f) (=)"'
xet + x – 2e + 2
x² e
4xe"
2х + 6е" — 6
-
-
-
x3
x4
(steps can be seen here).
1
Evaluate the 2nd derivative at the given point: (f (0))"
12

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