Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 1:**
Explain how to make 100 mL of 1M HCl from a 6M HCl stock solution. Show your calculation.
**Solution:**
To prepare a diluted solution, you can use the formula for dilution:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) = concentration of the stock solution
- \( V_1 \) = volume of the stock solution needed
- \( C_2 \) = concentration of the desired solution
- \( V_2 \) = volume of the desired solution
Given:
- \( C_1 = 6M \)
- \( C_2 = 1M \)
- \( V_2 = 100 \, \text{mL} \)
We need to find \( V_1 \).
Substitute the known values into the formula:
\[ 6M \times V_1 = 1M \times 100 \, \text{mL} \]
\[ 6V_1 = 100 \]
\[ V_1 = \frac{100}{6} \]
\[ V_1 \approx 16.67 \, \text{mL} \]
Therefore, to make 100 mL of 1M HCl, you should take approximately 16.67 mL of the 6M HCl stock solution and dilute it with water up to 100 mL.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa86b2d75-dc89-44ee-816d-e64b811f53cb%2Ff92b5851-faa8-4e82-9e1f-f72fedc136d9%2Fyh1yqay_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 1:**
Explain how to make 100 mL of 1M HCl from a 6M HCl stock solution. Show your calculation.
**Solution:**
To prepare a diluted solution, you can use the formula for dilution:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) = concentration of the stock solution
- \( V_1 \) = volume of the stock solution needed
- \( C_2 \) = concentration of the desired solution
- \( V_2 \) = volume of the desired solution
Given:
- \( C_1 = 6M \)
- \( C_2 = 1M \)
- \( V_2 = 100 \, \text{mL} \)
We need to find \( V_1 \).
Substitute the known values into the formula:
\[ 6M \times V_1 = 1M \times 100 \, \text{mL} \]
\[ 6V_1 = 100 \]
\[ V_1 = \frac{100}{6} \]
\[ V_1 \approx 16.67 \, \text{mL} \]
Therefore, to make 100 mL of 1M HCl, you should take approximately 16.67 mL of the 6M HCl stock solution and dilute it with water up to 100 mL.
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