1. Explain how to make 100 mL of 1M HCI from a 6M HCI stock solution. Show your calculation.

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**Question 1:**

Explain how to make 100 mL of 1M HCl from a 6M HCl stock solution. Show your calculation.

**Solution:**

To prepare a diluted solution, you can use the formula for dilution:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) = concentration of the stock solution
- \( V_1 \) = volume of the stock solution needed
- \( C_2 \) = concentration of the desired solution
- \( V_2 \) = volume of the desired solution

Given:
- \( C_1 = 6M \)
- \( C_2 = 1M \)
- \( V_2 = 100 \, \text{mL} \)

We need to find \( V_1 \).

Substitute the known values into the formula:

\[ 6M \times V_1 = 1M \times 100 \, \text{mL} \]

\[ 6V_1 = 100 \]

\[ V_1 = \frac{100}{6} \]

\[ V_1 \approx 16.67 \, \text{mL} \]

Therefore, to make 100 mL of 1M HCl, you should take approximately 16.67 mL of the 6M HCl stock solution and dilute it with water up to 100 mL.
Transcribed Image Text:**Question 1:** Explain how to make 100 mL of 1M HCl from a 6M HCl stock solution. Show your calculation. **Solution:** To prepare a diluted solution, you can use the formula for dilution: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) = concentration of the stock solution - \( V_1 \) = volume of the stock solution needed - \( C_2 \) = concentration of the desired solution - \( V_2 \) = volume of the desired solution Given: - \( C_1 = 6M \) - \( C_2 = 1M \) - \( V_2 = 100 \, \text{mL} \) We need to find \( V_1 \). Substitute the known values into the formula: \[ 6M \times V_1 = 1M \times 100 \, \text{mL} \] \[ 6V_1 = 100 \] \[ V_1 = \frac{100}{6} \] \[ V_1 \approx 16.67 \, \text{mL} \] Therefore, to make 100 mL of 1M HCl, you should take approximately 16.67 mL of the 6M HCl stock solution and dilute it with water up to 100 mL.
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