1. еxcess CHa/K,COОЗ 2. Ag20, H20 3. Д 1. еxcess CH3|K,CОЗ 2. Ag20, H20 3. А CH;NCH,CH,CH,CH=CH, CH,=CHCH,CH=CH, 1,4-рentadiene ČH3 piperidine
1. еxcess CHa/K,COОЗ 2. Ag20, H20 3. Д 1. еxcess CH3|K,CОЗ 2. Ag20, H20 3. А CH;NCH,CH,CH,CH=CH, CH,=CHCH,CH=CH, 1,4-рentadiene ČH3 piperidine
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
piperidine undergoes the series of reactions shown here, 1,4-pentadiene is obtained as the product. When the four different methyl-substituted
piperidines undergo the same series of reactions, each forms a different diene: 1,5-hexadiene; 1,4-pentadiene; 2-methyl-1,4-pentadiene; and
3-methyl-1,4-pentadiene. Which methyl-substituted piperidine forms which diene?
![1. еxcess CHa/K,COОЗ
2. Ag20, H20
3. Д
1. еxcess CH3|K,CОЗ
2. Ag20, H20
3. А
CH;NCH,CH,CH,CH=CH,
CH,=CHCH,CH=CH,
1,4-рentadiene
ČH3
piperidine](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ab58c2e-b628-4b36-b903-bfe5ab53f1f2%2Fd0d6a3ee-5eaa-4559-b595-8014b80ae8c1%2Fgicef8.png&w=3840&q=75)
Transcribed Image Text:1. еxcess CHa/K,COОЗ
2. Ag20, H20
3. Д
1. еxcess CH3|K,CОЗ
2. Ag20, H20
3. А
CH;NCH,CH,CH,CH=CH,
CH,=CHCH,CH=CH,
1,4-рentadiene
ČH3
piperidine
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