1. Define a function extract_grade(x):• x: A string containing a student number and grade in the format "studentNum-Grade%"• Return: The student's grade as a float.(Hint: Use the .split() and .strip() methods)1. Define a function class_average(final_marks):final_marks: A list of strings, where each string is formatted as "studentNum-Grade%".• Return: The mean grade of the grades in final_marks calculated using equation (1) outlined below.(Hint: Use your extract_grade function and a for loop!)N-11x =Ni=02. Define a function class_std_dev(final_marks):final_marks: A list of strings, where each string is formatted as "studentNum-Grade%".Return: The standard deviation of the grades in final_marks calculated using equation (2) outlined below.(Hint: Use your class_average function and a for loop!)N-11O =i=0 Generating statistics from a set of data is a task that computers love. In this assignment, you will be implementing a grade processing system that willgenerate the mean and standard deviation for a set of final exam grades.We will assume that final grades are stored in a list, where each entry in the list is a string with the following format:"studentNum-finalGrade%"The string represents the final exam mark (finalGrade) that the student (studentNum) achieved. For example, the cell below contains a list of final exam marksfrom two students. Student 1007089 achieved a mark of 91%, and student 1009989 achieved a mark of 77.5%.grades = ['1007089-91%','1009989-77.5%' ]We want to calculate the mean final exam mark from a list of grades. If we assume that we have N grades, the mean x can be calculated from the followingformula:N-11(1)i=0The variable x; represents each grade in our list at index i. We assume that we start counting at 0.We also want to be able to calculate the standard deviation from a list of grades. The standard deviation measures the amount of variability in our data set. Forexample, let's say we want to compute the average and standard deviation for the grades [80, 90, 70, 60]. The average of these grades is 75, and thestandard deviation is 11.2. Now imagine we want to compute the average and standard deviation for the grades [80, 76 ,74, 70]. The average of these gradesis 75, but the standard deviation is 3.6. Although both sets of grades have the same average, the second set has a smaller standard deviation. The reason isbecause the grades are not as "spread out" as the grades in the first set. The grades in the second set deviate from their average by a small amount.The standard deviation o is calculated using our mean x and the following formula:N-11>(x; -(2)O =i=0

We need to Define a function extract_grade(x) , class_average(final_marks) ,std_dev(final_marks):

1. Define a function extract_grade(x): • x: A string containing a student number and grade in the format "studentNum-Grade%" • Return: The student's grade as a float. (Hint: Use the .split() and .strip() methods) 1. Define a function class_average(final_marks): final_marks: A list of strings, where each string is formatted as "studentNum-Grade%". • Return: The mean grade of the grades in final_marks calculated using equation (1) outlined below. (Hint: Use your extract_grade function and a for loop!) N-1 1 N i=0 2. Define a function class_std_dev(final_marks): • final_marks: A list of strings, where each string is formatted as "studentNum-Grade%". • Return: The standard deviation of the grades in final_marks calculated using equation (2) outlined below. (Hint: Use your class_average function and a for loop!) N-1 1 E(xi - O = N i=0

1. Define a function extract_grade(x): • x: A string containing a student number and grade in the format "studentNum-Grade%" • Return: The student's grade as a float. (Hint: Use the .split() and .strip() methods) 1. Define a function class_average(final_marks): final_marks: A list of strings, where each string is formatted as "studentNum-Grade%". • Return: The mean grade of the grades in final_marks calculated using equation (1) outlined below. (Hint: Use your extract_grade function and a for loop!) N-1 1 N i=0 2. Define a function class_std_dev(final_marks): • final_marks: A list of strings, where each string is formatted as "studentNum-Grade%". • Return: The standard deviation of the grades in final_marks calculated using equation (2) outlined below. (Hint: Use your class_average function and a for loop!) N-1 1 E(xi - O = N i=0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Complete the following Code
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