1. DC circuit training system. 2. Set of wires. 3. DC Power supply. 4. Digital A.V.O. meter. Procedure: Part 1: Voltage Divider Rule 1. Using the DC circuit trainer, connect the circuit shown in Figi1). Take E-12V, RI-472, R2 = 1002 and R3 -2202. 2. Measured the voltage and current of "RI, R2 & R3". 3. Exchange the value of resistors as following: RI=I KN. R2-4702, R3- 330n

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
Question
15)
Part 2: Current Divider Rule
1. Using the DC circuit trainer, connect the circuit shown in Fig.(2),
Take E =10V, R1=2202 and R2 = 1002.
2. Measure the voltage and current of R1, R2.
3. Exchange the value of resistors as follows:
R1-ΙKΩ , R2-680 Ω.
Current Divider Rule:
The Current Divider Rule (CDR) states that the current through one of two parallel
branches is equal to the resistance of the other branch divided by the sum of the
resistances of the two parallel branches and multiplied by the total current entering
the two parallel branches in Fig.(2). That is:
Divider Rules
Objective: To verify the voltage divider rule (VDR) and the current divider rule
(CDR).
Discussion:
1- Comment on your results.
2- Compare between the practical and theoretical results.
3- When is used VDR and CDR.
R,
R
Theory:
Voltage Divider Rule:
The Voltage Divider Rule (VDR) states that the voltage across an element or acros
a series combination of elements in a series circuit is equal to the resistance of the
element or series combination of elements divided by the total resistance of the
series circuit and multiplied by the total impressed voltage in Fig. (1):
4- For the circuit shown in Fig.(3) calculate Vout.
Fig.(2)
V/R1
R2
R2
Or 1 =
* Iş
1
R1 + R2
R1+R2
V(RI+R2
R, - 1002
R -6052
R-12
Similarly, the current flowing through the R2 can be obtained as:
R,
R1
www
%3D
E- 100volt
R1+ R2
It can be noted that the expression for I2 has R, on its top line, that for I has R2 on its
Fig. (3)
top line.
E
5- Determine I1, I2, Iz and Is using only current divider formula when
Fig.(1)
Apparatus:
1. DC circuit training system.
412
2. Set of wires.
3. DC Power supply.
4. Digital A.V.O. meter.
Vout =
IR
Rn
..(1)
R1+R2+R3+-+Rn
6
Indicates that the voltage across any resistor Ri (i= 1, 2 , .
equal to the applied voltage (E) across the circuit multiplied by a factor
n ) in a series circuit i:
512
......
I-4A.
Procedure:
Ri
Part 1: Voltage Divider Rule
1. Using the DC circuit trainer, connect the circuit shown in Fig.(1),
Take E =12V, RI=472, R2 = 1002 and R3 =220N.
2f-1 Rj
%3D
2. Measured the voltage and current of "R1, R2 & R3".
3. Exchange the value of resistors as following:
R1-1 ΚΩ, R2-470Ω, R3-330 Ω.
It should be noted that this expression is only valid if the same current I flows
through all the resistors.
Transcribed Image Text:15) Part 2: Current Divider Rule 1. Using the DC circuit trainer, connect the circuit shown in Fig.(2), Take E =10V, R1=2202 and R2 = 1002. 2. Measure the voltage and current of R1, R2. 3. Exchange the value of resistors as follows: R1-ΙKΩ , R2-680 Ω. Current Divider Rule: The Current Divider Rule (CDR) states that the current through one of two parallel branches is equal to the resistance of the other branch divided by the sum of the resistances of the two parallel branches and multiplied by the total current entering the two parallel branches in Fig.(2). That is: Divider Rules Objective: To verify the voltage divider rule (VDR) and the current divider rule (CDR). Discussion: 1- Comment on your results. 2- Compare between the practical and theoretical results. 3- When is used VDR and CDR. R, R Theory: Voltage Divider Rule: The Voltage Divider Rule (VDR) states that the voltage across an element or acros a series combination of elements in a series circuit is equal to the resistance of the element or series combination of elements divided by the total resistance of the series circuit and multiplied by the total impressed voltage in Fig. (1): 4- For the circuit shown in Fig.(3) calculate Vout. Fig.(2) V/R1 R2 R2 Or 1 = * Iş 1 R1 + R2 R1+R2 V(RI+R2 R, - 1002 R -6052 R-12 Similarly, the current flowing through the R2 can be obtained as: R, R1 www %3D E- 100volt R1+ R2 It can be noted that the expression for I2 has R, on its top line, that for I has R2 on its Fig. (3) top line. E 5- Determine I1, I2, Iz and Is using only current divider formula when Fig.(1) Apparatus: 1. DC circuit training system. 412 2. Set of wires. 3. DC Power supply. 4. Digital A.V.O. meter. Vout = IR Rn ..(1) R1+R2+R3+-+Rn 6 Indicates that the voltage across any resistor Ri (i= 1, 2 , . equal to the applied voltage (E) across the circuit multiplied by a factor n ) in a series circuit i: 512 ...... I-4A. Procedure: Ri Part 1: Voltage Divider Rule 1. Using the DC circuit trainer, connect the circuit shown in Fig.(1), Take E =12V, RI=472, R2 = 1002 and R3 =220N. 2f-1 Rj %3D 2. Measured the voltage and current of "R1, R2 & R3". 3. Exchange the value of resistors as following: R1-1 ΚΩ, R2-470Ω, R3-330 Ω. It should be noted that this expression is only valid if the same current I flows through all the resistors.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
KVL and KCL
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,