1. Data were collected to explain the satisfaction rating a caller gives a customer representative based on the amount of time the caller is on hold (hold time is expressed in minutes) Complete the Table Below Regression Statistics Multiple R R Square Adjusted R Square 0.661 Stondord Error
1. Data were collected to explain the satisfaction rating a caller gives a customer representative based on the amount of time the caller is on hold (hold time is expressed in minutes) Complete the Table Below Regression Statistics Multiple R R Square Adjusted R Square 0.661 Stondord Error
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
Data were collected to explain the satisfaction rating a caller gives a customer representative based on the amount of time the caller is on hold (hold time is expressed in minutes)
*COMPLETE THE TABLE BELOW*
![1. Data were collected to explain the satisfaction rating a caller gives a customer representative based on
the amount of time the caller is on hold (hold time is expressed in minutes)
Complete the Table Below
Regression
Statistics
Multiple R
R Square
Adjusted R Square
0.661
Standard Error
Observations
10
ANOVA
Significance
F
df
MS
Regression
Residual
58.7
0.0026
25.3
Total
Standard
Error
Upper
95%
Coefficients
t Stat
P-value
Lower 95%
Intercept
23.90
4.430
0.0006499
Hold time
-1.30
0.303
0.003
Based on the regression results, answer the following questions
a) What is the estimated regression equation?
Rating =23.90 - 1,30 told time.
b) What percentage of the variation in the rating is explained by hold time?
Residual Ss€ =25.3
SST = 5SR +55€ - 58.7725,3=85
R? = SSR/SST = 587/84.
Regression sSR =58.7
Percentage of varation (o.c98)100. = c9.997
What is the standard error of the error term in the regression equatión?
mSE =5SE/aflerror) $25.318=3,1625 sE = NB,1625) = 1,7783
SS E =25.3
Standard error of error
1,7783
term
n=10
10-| = 9
d) Is the coefficient on the variable “hold timę" statistically significantly different than 0 at the 10%
level of significance? How do you know? (yeS, the coef on tne varjable hold time is stat.
Ho RI =0
HA: BI#O
Rexct null hye since p-valueca0.10 *nsUffient ev to conclude that Bichold +na
n = 10 observation
Test statr
K=I Ind. vari.
B1= -1.30
SE(BI)=0.303 e) What is the predicted rating if a caller is on hold for 10 minutes?' ? Statisticaly significant *
-300,303 t
-4.29 04
P -value=o,.003
Rating = 23,90-1,30 hold time
To prodict the rating wher hold time is equal to lomin
Rating : 23, 30 - 1.30 hold time
Predicted
rating
=23.90-1.30x10
rating 23,90-1 Ratingla.9o
10,90](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68cc5e62-1f1e-447e-86e2-72966307f0c4%2F23aa03ec-deb9-477d-ae58-bf58a23d7b68%2Fmckp7x_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Data were collected to explain the satisfaction rating a caller gives a customer representative based on
the amount of time the caller is on hold (hold time is expressed in minutes)
Complete the Table Below
Regression
Statistics
Multiple R
R Square
Adjusted R Square
0.661
Standard Error
Observations
10
ANOVA
Significance
F
df
MS
Regression
Residual
58.7
0.0026
25.3
Total
Standard
Error
Upper
95%
Coefficients
t Stat
P-value
Lower 95%
Intercept
23.90
4.430
0.0006499
Hold time
-1.30
0.303
0.003
Based on the regression results, answer the following questions
a) What is the estimated regression equation?
Rating =23.90 - 1,30 told time.
b) What percentage of the variation in the rating is explained by hold time?
Residual Ss€ =25.3
SST = 5SR +55€ - 58.7725,3=85
R? = SSR/SST = 587/84.
Regression sSR =58.7
Percentage of varation (o.c98)100. = c9.997
What is the standard error of the error term in the regression equatión?
mSE =5SE/aflerror) $25.318=3,1625 sE = NB,1625) = 1,7783
SS E =25.3
Standard error of error
1,7783
term
n=10
10-| = 9
d) Is the coefficient on the variable “hold timę" statistically significantly different than 0 at the 10%
level of significance? How do you know? (yeS, the coef on tne varjable hold time is stat.
Ho RI =0
HA: BI#O
Rexct null hye since p-valueca0.10 *nsUffient ev to conclude that Bichold +na
n = 10 observation
Test statr
K=I Ind. vari.
B1= -1.30
SE(BI)=0.303 e) What is the predicted rating if a caller is on hold for 10 minutes?' ? Statisticaly significant *
-300,303 t
-4.29 04
P -value=o,.003
Rating = 23,90-1,30 hold time
To prodict the rating wher hold time is equal to lomin
Rating : 23, 30 - 1.30 hold time
Predicted
rating
=23.90-1.30x10
rating 23,90-1 Ratingla.9o
10,90
![) What is the effect on rating of increasing the hold time by 1 minute?
g) What is the 95% confidence interval for the coefficient of hold time?
f) interpretatio n of Slope
the hold time
I then the predicted or
expected
As
Increasing
rating
decreases
by
-1.30
AS Increasing the hold time by !, then the effertsaa
matrny
decreases by -130
gJ The 95% confiderce interaval for the Coeficent of minute held te
is (-1,9983, -0,6013)
8' + tal2, n-zx SE(B') at a-os ta/2, n-2 =-
(-130*0698)18) (- 130 -0698718, - 1.30+0,698718)Ei.99818, -1,998)18, o.601212)
to 025,8=2.306 - 1,302,306 X0, 303
(-1,9987,0.013)
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68cc5e62-1f1e-447e-86e2-72966307f0c4%2F23aa03ec-deb9-477d-ae58-bf58a23d7b68%2F6nxaey_processed.jpeg&w=3840&q=75)
Transcribed Image Text:) What is the effect on rating of increasing the hold time by 1 minute?
g) What is the 95% confidence interval for the coefficient of hold time?
f) interpretatio n of Slope
the hold time
I then the predicted or
expected
As
Increasing
rating
decreases
by
-1.30
AS Increasing the hold time by !, then the effertsaa
matrny
decreases by -130
gJ The 95% confiderce interaval for the Coeficent of minute held te
is (-1,9983, -0,6013)
8' + tal2, n-zx SE(B') at a-os ta/2, n-2 =-
(-130*0698)18) (- 130 -0698718, - 1.30+0,698718)Ei.99818, -1,998)18, o.601212)
to 025,8=2.306 - 1,302,306 X0, 303
(-1,9987,0.013)
2
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