1. Create a dataset like the example below with the given data. D * Example x Y z PU ID 7.0 1.0 3.12 3.2760 NaN 4.0 1.0 4.16 4.3680 NaN 2.0 0.0 5.20 5.4600 NaN 3 3 3.0 1.0 1.35 1.4175 NaN 4 4 NaN 0.0 1.77 1.8585 6.0 5.0 1.0 2.80 2.9400 4.0 6. 7.0 0.0 5.75 6.0375 NaN 7 3.0 0.0 6.02 6.3210 2.0 8 1.0 1.0 7.21 7.5705 7.0 9 0.0 1.0 8.44 8.8620 NaN 10 10 5.0 NaN 9.43 9.9015 NaN 2. Treat the missing value in column X using replacement with the median value. 3. Draw a box plot of column X after completing Question-2. 2.
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- Match the result of the following expressions in hexadecimal. Question 1 options: 11111000 | 00111111 11111000 ^ 00111111 11111000 & 00111111 1. 2 0x38 3. OxFF 4. 0x00 5. 6. OxDB OxC7 OXF5Next time you snap a picture, you realize you are capturing millions of pixels into a buffer. The buffer data is read and converted into JPEG in real time. Each pixel in that buffer is an unsigned int (four bytes ): Alpha, Blue, Green, and Red. Let us ignore alpha for now. As you know, a unsigned byte can have a value 0 to 255. In remote sensing jargons, it is called blue channel, green channel, and red channel. Each channel provides valuable information such as, say farm lands, forest fire, drought, landscape, diseases , If a pixel has a value (say in hex) = 0x00a1b1c1 , then 0xc1 is the red pixel, 0xb1 is the green pixel, 0xa1 is the blue and 00 is the alpha. #define RED 1 #define GREEN 2 #define BLUE 3 then, develop a function void calculateSum ( unsigned int *ptr , int count , unsigned char channel , unsigned int *sum, float *average ) { *sum = 0; if (channel == RED ) calculate sum and average for red channel else if (channel == GREEN )…One method that can be used to compress text data is run length encoding (RLE). When RLE is used the compressed data can be represented as a set of character/frequency pairs. When the same character appears in consecutive locations in the original text it is replaced in the compressed text by a single instance of the character followed by a number indicating the number of consecutive instances of that character. Single instances of a character are represented by the character followed by the number 1. Figure 9 and Figure 10 show examples of how text would be compressed using this method. Figure 9 Original text: AAARRRRGGGHH Compressed text: A 3 R 4 G 3 H 2 Figure 10 Original text: CUTLASSES Compressed text: C 1 U 1 T 1 L 1 A 1 S 2 E 1 S 1 What you need to do Task 1 Write a Python program that will perform the compression process described above. The program should display a suitable prompt asking the user to input the text to compress and then output the compressed text. Task 2 Test…
- Please write a MIPS code to draw the below shape on a bitmap display. Consider the square to have m size and draw the two black diagonal lines inside the square as shown. Please keep it simple and do it as a MIPS code on bitmap display. thank you1165:0100 B84518 1165:0103 BB3478 1165:0106 01C3 1165:0108 48 1165:0109 4B 1165:010A 891E0001 1165 : 01 ΘΕ CD20 AX, 1845 BX, 7834 BX, AX AX MOV MOV ADD DEC DEC BX MOV (01001, BX INT 20 You have used DEBUG to unassemble the above code. The entire program is bytes long.1. Decipher the following codes: 01001101, 01100001, 01110100, 01101000, 01101001, 01110011, 01100001, 01101110, 01000001, 01110010, 01110100. Hint: 4 words.
- You have been given this "Boston" dataset below: crim zn indus chas nox rm age dis rad tax ptratio black Istat medv 0.00632 18.0 2.31 0 0.538 6.575 65.2 4.0900 1 296 15.3 396.90 4.98 24.0 0.02731 0.0 7.07 0 0.469 6.421 78.9 4.9671 2 242 17.8 396.90 9.14 21.6 0.02729 0.0 7.07 0 0.469 7.185 61.1 4.9671 2 242 17.8 392.83 4.03 34.7 0.03237 0.0 2.18 0 0.458 8.998 45.8 6.0622 3 222 18.7 394.63 2.94 33.4 0.06905 0.0 2.18 0 0.458 7.147 54.2 6.0622 3 222 18.7 396.90 5.33 36.2 How will you extract all the records where the rad value is equal to 3'?Assignment # 1 1. Convert 82ADh to decimal. 2. Convert 11101b to decimal. 3. Convert 2BD4h to decimal. 4. Convert 95 to binary. 5. Convert 2B3Ch to binary. 6. Convert 1110101010b to hex. 7. Add 3546d and 1872d. 8. Add 5B39h and 7AF4h. 9. Add 100101111b and 110110. 10. Subtract 7283d from 9145d. 11. Subtract BA94h from D26Fh. 12. Subtract 0111b from 1001. 13. Find one’s compliment of 5. 14. Find two’s compliment of 5. 15. Find two’s compliment of the two’s compliment of 5. 16. In many applications, it saves time to memorize the conversions among small binary, decimal, and hex numbers. Fill in the blanks in the following table: Binary Decimal Hex _____ 9 _____ 1010 _____ _____ _____ _____ D _____ 12 _____ 1110 _____ _____ _____ _____ B 17. Convert the following binary and hex numbers to decimal: a. 1110 b. 100101011101 c. 46Ah d. FAE2Ch 18. Convert the following numbers: a. 1001011 to hex b. 1001010110101110 to hex c. A2Ch to binary d. B34Dh to binary 19. Perform the following additions:…The figure below represents the Differential Manchester encoding of a data stream. What is the data stream? D. Manchester does not require block coding, explain briefly. Time
- Assignment # 11. Convert 82ADh to decimal.2. Convert 11101b to decimal.3. Convert 2BD4h to decimal.4. Convert 95 to binary.5. Convert 2B3Ch to binary.6. Convert 1110101010b to hex.7. Add 3546d and 1872d.8. Add 5B39h and 7AF4h.9. Add 100101111b and 110110.10. Subtract 7283d from 9145d.11. Subtract BA94h from D26Fh.12. Subtract 0111b from 1001.13. Find one’s compliment of 5.14. Find two’s compliment of 5.15. Find two’s compliment of the two’s compliment of 5.16. In many applications, it saves time to memorize the conversions among small binary, decimal, and hex numbers. Fill in the blanks in the following table:Binary Decimal Hex_____ 9 _____1010 _____ __________ _____ D_____ 12 _____1110 _____ __________ _____ B 17. Convert the following binary and hex numbers to decimal:a. 1110b. 100101011101c. 46Ahd. FAE2Ch18. Convert the following numbers:a. 1001011 to hexb. 1001010110101110 to hexc. A2Ch to binaryd. B34Dh to binary19. Perform the following additions:a. 100101b + 10111bb. 100111101b…V:OA I docs.google.com/forms نقطة واحدة In system, the information go in only one way the same time. (DX, SX, * .HDX, RX) SX RX O HDX O TX O نقطة واحدة Given a TV channel in the band 78-80 MHz, the minimum sampling frequency is_MHz 160 144 200 12Decoding Data Instructions Hint: First do Google search for ‘packet dump decode’. Then cut and paste the block of data below into the input data section. Then press decode. You will be able to find the answer from the decoding result. For the payload of the application layer, take the last few bytes in ASCII. It’s not in the packet dump, because it is not a part of header. You can use the ASCII character table to manually convert them. If you understanding the layer 4 destination port #, you understand what it is asking for. There is only one kind of information for the port #. Data block to be decoded: 00 11 bc b5 49 40 b8 8d 12 00 0d fa 08 00 45 00 00 37 99 09 00 00 ff 11 ea 9f 0a 07 03 1a 42 aa e8 41 c7 19 00 35 00 23 a3 9e 02 90 01 00 00 01 00 00 00 00 00 00 05 6d 69 74 72 65 03 6f 72 67 00 00 01 00 01 Please answer the following question after decoded the above data block: Q1: (Layer 4) Protocol is:, Source MAC address:, Destination MAC address:, Source IP…