Answered: 1. Consider the two-loop circuit… | bartleby

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1. Consider the two-loop circuit sketched below. Find the current passing
through each battery, and calculate the rate at which energy is delivered to the
circuit by the two batteries.
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10. a circuit consisting of a battery with an emt of 12V, a vesistor with a resistance of 1.2h2, a capacitor with a capacitance of 0.05F, and another capacitor with a capacitance of 0.2F are all connected in series with a switch. Initially, both capacitors are empty. When the switch is closed, a) now long will it take each capacitor to reach a charge of V. 2880? b) at that time, what is the current through the resistor? c) at that time, what are the potentials across the resistor and each capacitor?
9. The following question is about power dissipation in a resistor, which we didnÃ¢ÂÂt really cover in class. This topic is fairly easy though. In a circuit, all the power delivered by the battery must be dissipated by the elements to the circuit. This is simply a statement of the conservation of energy. How much energy dis- sipated depends on the resistance of the element and the voltage across the resistor, or the current through it. The relevant equa- tions for the problems are as follows. For a circuit element, the power dissipated (or generated) is P = IV, where V and I are the voltage across and current through a circuit element. We know that a resistor obeys OhmÃ¢ÂÂs Law V = IR, which means that for a resistor, the power dissipated is P = 1²R=V²/R. Consider the following two circuits with identical batteries and re- sistors. А В C R R R RS R If the power dissipated by the resistor in circuit A is P, what is the power dissipated by one resistor in circuit B? If the power…
Consider a circuit consisting of a battery and two bulbs. Explain why the following two statements are direct consequences of the preceding definitions. A. When two bulbs are connected in series, the same current that passes through one bulb must also pass through the other. B. When two bulbs are connected in parallel, current that passes through one bulb does not pass through the other.
The time constant in an RC circuit is the time it takes a. so that the current drops to zero. b. so that the current reaches its maximum value c. so that the capacitor is fully charged. d. in which the current decreases to 37% of its initial value.
14. A power supply providing 85 V is hooked in series to a lightbulb, using two connecting wires. The lightbulb has a resistance bulb B. of 130 N and the wires have a resistance of 15 2 each. The actual question is, how much power does the bulb use, and how much power is lost in the wires? This is broken down into steps. a. What is the equivalent resistance of the series circuit? [160 Q] b. What is the current through the circuit? [.53 A] c. What is the magnitude of the potential difference between points A and B? (What is the voltage across wire 1?) [8 V] d. What is the magnitude of the potential difference between points wire 1 wire 2 A B and C? (What is the voltage across the bulb?) [69 V – note that the voltage across the bulb is NOT the 85 V of the power supply. The sum of the voltages, 8+69+8, around the circuit, IS the voltage of the power supply.) e. How much power is used by the bulb? [36.6 W] f. How much power is lost in the one of the wires? [4.2 W] |