14. A power supply providing 85 V is hooked in series to a lightbulb, using two connecting wires. The lightbulb has a resistance bulb of 130 N and the wires have a resistance of 15 N each. The actual question is, how much power does the bulb use, and how much power is lost in the wires? This is broken down into steps. a. What is the equivalent resistance of the series circuit? [160 N] b. What is the current through the circuit? [.53 A] c. What is the magnitude of the potential difference between points A and B? (What is the voltage across wire 1?) [8 V] d. What is the magnitude of the potential difference between points wire wire 2 A B and C? (What is the voltage across the bulb?) [69 V – note that the voltage across the bulb is NOT the 85 V of the power supply. The sum of the voltages, 8+69+8, around the circuit, IS the voltage of the power supply.) e. How much power is used by the bulb? [36.6 W] f. How much power is lost in the one of the wires? [4.2 W]

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Chapter1: Units, Trigonometry. And Vectors
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14. A power supply providing 85 V is hooked in series to a
lightbulb, using two connecting wires. The lightbulb has a resistance
bulb
B.
of 130 N and the wires have a resistance of 15 2 each. The actual
question is, how much power does the bulb use, and how much
power is lost in the wires? This is broken down into steps.
a. What is the equivalent resistance of the series circuit? [160 Q]
b. What is the current through the circuit? [.53 A]
c. What is the magnitude of the potential difference between points
A and B? (What is the voltage across wire 1?) [8 V]
d. What is the magnitude of the potential difference between points
wire 1
wire 2
A
B and C? (What is the voltage across the bulb?) [69 V – note that the voltage across the bulb is NOT the 85 V
of the power supply. The sum of the voltages, 8+69+8, around the circuit, IS the voltage of the power supply.)
e. How much power is used by the bulb? [36.6 W]
f. How much power is lost in the one of the wires? [4.2 W]
|
Transcribed Image Text:14. A power supply providing 85 V is hooked in series to a lightbulb, using two connecting wires. The lightbulb has a resistance bulb B. of 130 N and the wires have a resistance of 15 2 each. The actual question is, how much power does the bulb use, and how much power is lost in the wires? This is broken down into steps. a. What is the equivalent resistance of the series circuit? [160 Q] b. What is the current through the circuit? [.53 A] c. What is the magnitude of the potential difference between points A and B? (What is the voltage across wire 1?) [8 V] d. What is the magnitude of the potential difference between points wire 1 wire 2 A B and C? (What is the voltage across the bulb?) [69 V – note that the voltage across the bulb is NOT the 85 V of the power supply. The sum of the voltages, 8+69+8, around the circuit, IS the voltage of the power supply.) e. How much power is used by the bulb? [36.6 W] f. How much power is lost in the one of the wires? [4.2 W] |
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