1. Consider the following figure. M P M (a)Compute the vector gravitational field at a point P on the perpendicular bisector of the line joining two objects of equa mass separated by a distance 2a as shown in the figure above. 2GMr (you should get g (r2 + a²)?' (b) Explain physically why the field should approach zero as r 0. (c) Prove mathematically that the answer to part (a) behaves
1. Consider the following figure. M P M (a)Compute the vector gravitational field at a point P on the perpendicular bisector of the line joining two objects of equa mass separated by a distance 2a as shown in the figure above. 2GMr (you should get g (r2 + a²)?' (b) Explain physically why the field should approach zero as r 0. (c) Prove mathematically that the answer to part (a) behaves
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
Transcribed Image Text:1. Consider the following figure.
M
P
a
M
(a)Compute the vector gravitational field at a point P on the
perpendicular bisector of the line joining two objects of equal
mass separated by a distance 2a as shown in the figure
above.
2GMT
(you should get g
(r2 + a²)??
(b) Explain physically why the field should approach zero
as r
0.
(c) Prove mathematically that the answer to part (a) behaves
in this way.
(d) Explain physically why the magnitude of the field should
2GM
approach
-as r → O0.
r2
(e) Prove mathematically that the answer to part (a) behaves
correctly in this limit.
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