1.) Consider the equilibrium reaction shown below: PCs(9) – PCb(9) + A;(g) Kc = 9.32 x 103 Calculate the equilibrium concentrations of all species when initially 0.250 M PCIS, 0.175 M PA3, and 0.115 M Clz are present.

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1.) Consider the equilibrium reaction shown below:
PCIS(9) = PCI3(9) + A½(g)
Kc = 9.32 x 103
Calculate the equilibrium concentrations of all species when initially 0.250 M PCI5, 0.175
M PA3, and 0.115 M Cl2 are present.
9.250
I @250
O 175
-0,08181-0.08181
Q= 0.0805>9.32xb
E0.250+x9.175-× o15X
9.32 xM0²= (0 175-x)(0.15->)
(0.250+ x)
(9.32 xb°) (0.250 +x)= (0.175x)(0, ||5-x)
0.00233 + 0.00n32x = 0.02o12ち-0.175x-0.Jらx +x
0.002 33 + 0.00932x
- 0.020125 - 0. 290x+x
Ø =X-0.290 × – 0.00932x + 0.0 20125 – 0.00233
Ø =x -
0.29932 x + 0.017795
-(-0,29932) ±r(-0.29932)*
(2) ()
- (4) (1) (0.017795)
×ニ
X=
0.29932±V.9184)
using (4): X= 0.37
using ☺:X=0. 08181
Transcribed Image Text:1.) Consider the equilibrium reaction shown below: PCIS(9) = PCI3(9) + A½(g) Kc = 9.32 x 103 Calculate the equilibrium concentrations of all species when initially 0.250 M PCI5, 0.175 M PA3, and 0.115 M Cl2 are present. 9.250 I @250 O 175 -0,08181-0.08181 Q= 0.0805>9.32xb E0.250+x9.175-× o15X 9.32 xM0²= (0 175-x)(0.15->) (0.250+ x) (9.32 xb°) (0.250 +x)= (0.175x)(0, ||5-x) 0.00233 + 0.00n32x = 0.02o12ち-0.175x-0.Jらx +x 0.002 33 + 0.00932x - 0.020125 - 0. 290x+x Ø =X-0.290 × – 0.00932x + 0.0 20125 – 0.00233 Ø =x - 0.29932 x + 0.017795 -(-0,29932) ±r(-0.29932)* (2) () - (4) (1) (0.017795) ×ニ X= 0.29932±V.9184) using (4): X= 0.37 using ☺:X=0. 08181
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