1. Compute the convolution sum of the following pairs of signals. (Lesson 3.1) x(п) — (0.9)" и(п) h(n) %3D (0.5)" и(п) x(п) — h(п) — (0.5)" и(п) n = -2,0,1 n = -1 1, x (п) %3D { 2, 0, elsewhere h(n) — 8(п) — 6(п — 1) + 6(п — 4) + 6(п — 5) x(п) — и(п + 1) — и(п — 4) — 8(n - 5) h(n) — [u(п + 2) — и(п — 3)] - (3 — In|) x(п) —D и(п) — и(п- 5) h(n) — и(п — 2) - и(п - 8) + u(п -11) - и(п - 17)
1. Compute the convolution sum of the following pairs of signals. (Lesson 3.1) x(п) — (0.9)" и(п) h(n) %3D (0.5)" и(п) x(п) — h(п) — (0.5)" и(п) n = -2,0,1 n = -1 1, x (п) %3D { 2, 0, elsewhere h(n) — 8(п) — 6(п — 1) + 6(п — 4) + 6(п — 5) x(п) — и(п + 1) — и(п — 4) — 8(n - 5) h(n) — [u(п + 2) — и(п — 3)] - (3 — In|) x(п) —D и(п) — и(п- 5) h(n) — и(п — 2) - и(п - 8) + u(п -11) - и(п - 17)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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with explanation please
(signals)
![1. Compute the convolution sum of the following pairs of signals. (Lesson 3.1)
x(п) — (0.9)" и(п)
h(n) %3D (0.5)" и(п)
x(п) — h(п) — (0.5)" и(п)
n = -2,0,1
n = -1
1,
x (п) %3D { 2,
0,
elsewhere
h(n) — 8(п) — 6(п — 1) + 6(п — 4) + 6(п — 5)
x(п) — и(п + 1) — и(п — 4) — 8(n - 5)
h(n) — [u(п + 2) — и(п — 3)] - (3 — In|)
x(п) — и(п) — и(п— 5)
h(n) — и(п — 2) - и(п - 8) + u(п -11) - и(п - 17)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F124e67f8-bf61-40e1-9d4c-05c76a90cfe9%2F067d587a-af5f-4d58-9c64-872a43d997be%2F7pk0oe_processed.png&w=3840&q=75)
Transcribed Image Text:1. Compute the convolution sum of the following pairs of signals. (Lesson 3.1)
x(п) — (0.9)" и(п)
h(n) %3D (0.5)" и(п)
x(п) — h(п) — (0.5)" и(п)
n = -2,0,1
n = -1
1,
x (п) %3D { 2,
0,
elsewhere
h(n) — 8(п) — 6(п — 1) + 6(п — 4) + 6(п — 5)
x(п) — и(п + 1) — и(п — 4) — 8(n - 5)
h(n) — [u(п + 2) — и(п — 3)] - (3 — In|)
x(п) — и(п) — и(п— 5)
h(n) — и(п — 2) - и(п - 8) + u(п -11) - и(п - 17)
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