1. Changing the number of positively charged protons in the nucleus of an element would form T a) a non-radioactive isotope of the elementT b)-a radioactive isotope of the element T c) a different element T d) an element that would be able to react with any known substanceT 2. If an atom of an element loses electrons to an atom of another element, e.g., sodium to chlorine T a) the atomic mass of sodium will decrease significantly T b) both sodium and chlorine produce isotopes of the element c) the charge on sodium becomes positive and that of chlorine becomes negative T d) All the above are correct T

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Changing the number of positively charged protons in the nucleus of an element would form T
a) a non-radioactive isotope of the elementT
b)-a radioactive isotope of the element T
c) a different element T
d) an element that would be able to react with any known substanceT
2.- If an atom of an element loses electrons to an atom of another element, e.g., sodium to chlorine T
a) the atomic mass of sodium will decrease significantly T
b) both sodium and chlorine produce isotopes of the elementT
c) the charge on sodium becomes positive and that of chlorine becomes negative T
d) All the above are correct T
Transcribed Image Text:1. Changing the number of positively charged protons in the nucleus of an element would form T a) a non-radioactive isotope of the elementT b)-a radioactive isotope of the element T c) a different element T d) an element that would be able to react with any known substanceT 2.- If an atom of an element loses electrons to an atom of another element, e.g., sodium to chlorine T a) the atomic mass of sodium will decrease significantly T b) both sodium and chlorine produce isotopes of the elementT c) the charge on sodium becomes positive and that of chlorine becomes negative T d) All the above are correct T
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