Question in image. i need help with q 2 BackgroundSiphoning, the process of using a tube to carry a liquidover a barrier and to a lower location, can be described wellbythe mechanical energy equation. In this assignment youwill analyse siphoning behaviour theoretically, and thenwill carry out an experiment using a plastic bottle andlength of tubing provided to you.The plastic bottle has a nominal volume of one litre.However, two marks have been placed on the side of thebottle such that the corresponding volume between the twoAZmarks is approximately AV = 650 cm3. The plastic tubinggiven to you has an inside diameter of D = 2 mm and alength of L = 100 cm. In the picture to the right, Az is thevariable distance between the liquid level in the bottle andthe tube outlet level.The diameter of the tube is small enough that the flow inside will be laminar, anorderly state of flow in which a = 2 in the mechanical energy equation. Furthermore,the friction (wterm canexpressed as wf = kFLuavgwhere k = 9.5s-1 is a friction constant for room-temperature laminar flow of water inthis particular tubing. L is end-to-end length of tube and yovg is the average velocity inthe tube. You may take the water density to be 999kg/m3.AnalysisForthis experiment the analysis will be performed first.1. Calculate the volumetric flow rate of the siphon (cm3/s), assuming that L=100cm,Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get thevolumetric flow rate, you must first calculate ygvg:2. Predict the volumetric flow rate of the siphon (cm3/s), assuming that L = 100cm,Az = 80cm, and that there is friction in the tube (wi given by equation above).3. Repeat the flow rate calculation from number 2 with the following change: assume ahalf-length of tubing is used, with L = 50 cm and Az = 33 cm1

Siphon: It is a pipe or tube that is used to transfer a fluid in fluid mechanics. It can be to…

1. Calculate the volumetricflow rate of the siphon (cm³/s), assuming that L= 100cm, Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get the volumetric flow rate, you must first calculate ygva, 2. Predict the volumetric flow rate of the siphon (cm³/s), assuming that L = 100 cm, Az = 80cm, and that there is friction in the tube (Wgiven by equation above). 3. Repeatthe flow rate calculation from number 2 with the following change: assume a half-length of tubing is used, with L = 50 cm and Az = 33 cm

1. Calculate the volumetricflow rate of the siphon (cm³/s), assuming that L= 100cm, Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get the volumetric flow rate, you must first calculate ygva, 2. Predict the volumetric flow rate of the siphon (cm³/s), assuming that L = 100 cm, Az = 80cm, and that there is friction in the tube (Wgiven by equation above). 3. Repeatthe flow rate calculation from number 2 with the following change: assume a half-length of tubing is used, with L = 50 cm and Az = 33 cm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Fluid Kinematics

The branch of science that deals with objects which are either in motion or stationary are studied under the branch of classical mechanics. Fluid mechanics is a subcategory of classical mechanics that deals with the behavior of fluids at rest (fluid statics) or in motion (posing some velocity). In fluid kinematics, studies focus on the associated motion of fluid particles or groups of particles, and its associated parameters like displacements, velocity, and acceleration without concerning about the forces that caused the motion. All the laws of classical mechanics are applied in the study of fluid kinematics.

Question

Question in image. i need help with q 2

Background
Siphoning, the process of using a tube to carry a liquid
over a barrier and to a lower location, can be described well
bythe mechanical energy equation. In this assignment you
will analyse siphoning behaviour theoretically, and then
will carry out an experiment using a plastic bottle and
length of tubing provided to you.
The plastic bottle has a nominal volume of one litre.
However, two marks have been placed on the side of the
bottle such that the corresponding volume between the two
AZ
marks is approximately AV = 650 cm3. The plastic tubing
given to you has an inside diameter of D = 2 mm and a
length of L = 100 cm. In the picture to the right, Az is the
variable distance between the liquid level in the bottle and
the tube outlet level.
The diameter of the tube is small enough that the flow inside will be laminar, an
orderly state of flow in which a = 2 in the mechanical energy equation. Furthermore,
the friction (wterm can
expressed as wf = kFLuavg
where k = 9.5s-1 is a friction constant for room-temperature laminar flow of water in
this particular tubing. L is end-to-end length of tube and yovg is the average velocity in
the tube. You may take the water density to be 999kg/m3.
Analysis
Forthis experiment the analysis will be performed first.
1. Calculate the volumetric flow rate of the siphon (cm3/s), assuming that L=100cm,
Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get the
volumetric flow rate, you must first calculate ygvg:
2. Predict the volumetric flow rate of the siphon (cm3/s), assuming that L = 100cm,
Az = 80cm, and that there is friction in the tube (wi given by equation above).
3. Repeat the flow rate calculation from number 2 with the following change: assume a
half-length of tubing is used, with L = 50 cm and Az = 33 cm
1

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