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1. Calculate the tension and acceleration in the pulley system shown below assuming that there is 0.30 friction on the incline. 5 kg 35° 7 kg Given: Type or insert image +

1. Calculate the tension and acceleration in the pulley system shown below assuming that there is 0.30 friction on the incline. 5 kg 35° 7 kg Given: Type or insert image +

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Kindly provide the solution to the following question using the GRASS method.  Motion and Forces (Dynamics Unit). Please show all your work.

 

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1. Calculate the tension and acceleration in the pulley system shown below assuming that there is 0.30 friction on the incline. 5 kg 35° 7 kg Given: Type or insert image Required: Type or insert image Analysis: Type or insert image Solution: Type or insert image + Statement Paraphrase: Type or insert image
Transcribed Image Text:1. Calculate the tension and acceleration in the pulley system shown below assuming that there is 0.30 friction on the incline. 5 kg 35° 7 kg Given: Type or insert image Required: Type or insert image Analysis: Type or insert image Solution: Type or insert image + Statement Paraphrase: Type or insert image
Motion Ad = Ad₁ + Ad₂ + ... b sin B a sin A V₂ V t VAB = VAC + VCB a av = = Forces āc F = ma = C sin C c²=a² + b² sin d t āav ( t)² 2 F = mã, Uniform Circular Motion 1² F = ma y=- d = v₁ t+ VXY = √xx ā = v= x = F m F₂ Unit 1 Dynamics = à t H cos -b+√b²-4ac 2a F = mg GMm ā= à = (v₁ + √₂) t 2 H V 7. t tan 0 = 1. A A==bh v² = ₁² +2αav F₁ = FN v=2-r V= T c²=a² + b² - 2ab cos 0 Y₂ Y₁ X₂ X₁ āav( t)² 2 ā F A = lw s,max N Slope= d=v₂ t a = 4 ² rf² T r=} V= FN GM r
Transcribed Image Text:Motion Ad = Ad₁ + Ad₂ + ... b sin B a sin A V₂ V t VAB = VAC + VCB a av = = Forces āc F = ma = C sin C c²=a² + b² sin d t āav ( t)² 2 F = mã, Uniform Circular Motion 1² F = ma y=- d = v₁ t+ VXY = √xx ā = v= x = F m F₂ Unit 1 Dynamics = à t H cos -b+√b²-4ac 2a F = mg GMm ā= à = (v₁ + √₂) t 2 H V 7. t tan 0 = 1. A A==bh v² = ₁² +2αav F₁ = FN v=2-r V= T c²=a² + b² - 2ab cos 0 Y₂ Y₁ X₂ X₁ āav( t)² 2 ā F A = lw s,max N Slope= d=v₂ t a = 4 ² rf² T r=} V= FN GM r
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