1. Calculate the steam consumption and the amount of juice per hour that can be concentrated from 12% to 20% solids content in an existing single effect evaporator with 30 m² heat transfer area. It is given that the juice enters the evaporator at 50°C, the boiling temperature in the evaporator is 60°C, and saturated steam at 100°C is used as the heating medium. Assume that the overall heat transfer coefficient is 1000 W/m²°C and the heat capacity of the juice is given by the equation Cp =1672 + 2508 Xw (in J/kg°C), where xw is the water mass fraction of the juice.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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1. Calculate the steam consumption and the amount of juice per hour that can be concentrated
from 12% to 20% solids content in an existing single effect evaporator with 30 m? heat transfer
area. It is given that the juice enters the evaporator at 50°C, the boiling temperature in the
evaporator is 60°C, and saturated steam at 100°C is used as the heating medium. Assume that
the overall heat transfer coefficient is 1000 W/m²°C and the heat capacity of the juice is given
by the equation cp =1672 + 2508 xw (in J/kg°C), where xw is the water mass fraction of the
juice.
Transcribed Image Text:1. Calculate the steam consumption and the amount of juice per hour that can be concentrated from 12% to 20% solids content in an existing single effect evaporator with 30 m? heat transfer area. It is given that the juice enters the evaporator at 50°C, the boiling temperature in the evaporator is 60°C, and saturated steam at 100°C is used as the heating medium. Assume that the overall heat transfer coefficient is 1000 W/m²°C and the heat capacity of the juice is given by the equation cp =1672 + 2508 xw (in J/kg°C), where xw is the water mass fraction of the juice.
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