1. Calculate the Index of Hydrogen Deficiency (IHD; also known as degree of unsaturation) for the following molecular formulas and place your response in the designated box. Then answer part (d). (2-6)+2-5-1 (26)+2+1 8) +2 -14) a. C8H₁40 a. IHD 2 b. C6H5CI b. IHD = 4 C6H7N c. IHD = 4 d. Propose two different combinations of bonding features to account for an IHD of 4 in a molecule consisting of C and H atoms and one O atom only (i.e. C,H,O). For example, a molecule with molecular formula CxHyO and IHD = 2 may have one C=O bond and one ring (this is an example of one combination). For this exercise, do not propose more than one ring. CxHyO, IHD= 4, combination 1 CxHyO, IHD = 4, combination 2

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1. Calculate the Index of Hydrogen Deficiency (IHD; also known as degree of unsaturation) for the following
molecular formulas and place your response in the designated box. Then answer part (d).
— [12-8) +2-14)
a. C8H₁40
a. IHD= = 2
(2-6) +2-5-1 b. C₂H5Cl
b. IHD = 4
{[(2·6)+2+¹ °C. C6H¬N
c. IHD = 4
d. Propose two different combinations of bonding features to account for an IHD of 4 in a molecule
consisting of C and H atoms and one O atom only (i.e. C,H,O). For example, a molecule with
molecular formula CxHyO and IHD = 2 may have one C=O bond and one ring (this is an example of
one combination). For this exercise, do not propose more than one ring.
CxHyO, IHD = 4, combination 1
CxHyO, IHD = 4, combination 2
Transcribed Image Text:1. Calculate the Index of Hydrogen Deficiency (IHD; also known as degree of unsaturation) for the following molecular formulas and place your response in the designated box. Then answer part (d). — [12-8) +2-14) a. C8H₁40 a. IHD= = 2 (2-6) +2-5-1 b. C₂H5Cl b. IHD = 4 {[(2·6)+2+¹ °C. C6H¬N c. IHD = 4 d. Propose two different combinations of bonding features to account for an IHD of 4 in a molecule consisting of C and H atoms and one O atom only (i.e. C,H,O). For example, a molecule with molecular formula CxHyO and IHD = 2 may have one C=O bond and one ring (this is an example of one combination). For this exercise, do not propose more than one ring. CxHyO, IHD = 4, combination 1 CxHyO, IHD = 4, combination 2
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