1. Calculate the H30* and OH concentrations according to the given ph valuesSolutionpH[H;O'][OH]Woboiled distilledwater9.02Boiled distilled water,6.541.0 M NaCl solution6.021.0 M NaHSO4solution0.731.0 M Na2CO3solution11.482. Calculate the Ka and Kb values for 1.0 M NaHSO4 and NazCOa.HydrolysisReactionExpression for Ku andK,Value of K andSoluteNaHSO4pH=0.73NazCO3pH= 11.48NaHSO,H20NaSO4H3o*NazCO3H20NazCHO,+ он 3. Сalculate the рH. [НЗО"1.[ОН]. Kа and a values.1.0 М1.0 МpH[H301[OH]pHHC2H3O2 [H30*]0.02HCIКаHCI2.30[OH]pHNH3(ag) [H30ʻ][OH]a11.8КаHC2H3O2aKbNH3(ag)aHClH20H;ơ + CĪHC,H3O, + H20H;O + C,H;O,[C,H,O] = [H,O]]%3DNH3 + H20OH+ NHÀ[NH] = [OH]

1. Çalculate the H3O* and OH çoncentrations according to the given ph values- Solution pH. [H,O°] [OH] Waboiled distilled water 9.02 Boiled distilled water, 1.0 M NaCl solution 6.54 6.02 1.0 M NaHSO4 solution 0.73 1.0 M Na2CO3 solution 11.48

1. Çalculate the H3O* and OH çoncentrations according to the given ph values- Solution pH. [H,O°] [OH] Waboiled distilled water 9.02 Boiled distilled water, 1.0 M NaCl solution 6.54 6.02 1.0 M NaHSO4 solution 0.73 1.0 M Na2CO3 solution 11.48

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

1. Calculate the H30* and OH concentrations according to the given ph values
Solution
pH
[H;O']
[OH]
Woboiled distilled
water
9.02
Boiled distilled water,
6.54
1.0 M NaCl solution
6.02
1.0 M NaHSO4
solution
0.73
1.0 M Na2CO3
solution
11.48
2. Calculate the Ka and Kb values for 1.0 M NaHSO4 and NazCOa.
Hydrolysis
Reaction
Expression for Ku and
K,
Value of K and
Solute
NaHSO4
pH=0.73
NazCO3
pH= 11.48
NaHSO,
H20
NaSO4
H3o*
NazCO3
H20
NazCHO,
+ он

3. Сalculate the рH. [НЗО"1.[ОН]. Kа and a values.
1.0 М
1.0 М
pH
[H301
[OH]
pH
HC2H3O2 [H30*]
0.02
HCI
Ка
HCI
2.30
[OH]
pH
NH3(ag) [H30ʻ]
[OH]
a
11.8
Ка
HC2H3O2
a
Kb
NH3(ag)
a
HCl
H20
H;ơ + CĪ
HC,H3O, + H20
H;O + C,H;O,
[C,H,O] = [H,O]
]
%3D
NH3 + H20
OH
+ NHÀ
[NH] = [OH]

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