1. Beam Diagram 27, CISC Handbook of Steel Construction, where w-uniformly distributed load. (a) Write the mathematic formulation for the overhanging span (where 0 < x≤ a) using 4th-order differential equation. A, from the span 0≤x≤1, given in the Beam Diagram, should be used to obtain the boundary conditions of the overhanging span at x₁-0. (b) Solve the differential equation for deflection Ax, ( . 27. BEAM OVERHANGING ONE SUPPORT RA 1+<+ M max 12- Shear Moment R UNIFORMLY DISTRIBUTED LOAD BETWEEN SUPPORTS Equivalent Tabular Load. R=V 1 WI ****** M max. (at center)....... My TRAV ORA 19TED TA 0404 OSTAL A max. (at center) A, A₁ wl 2 W *(1/2-x) w12 8 WX 2 (1-x) 5w/4 100 24 El w13x₁ 24 El MADD 384 El WX (13-2/x² + x³)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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FA(5:30PM)
or FB(1:00PM)
1. Beam Diagram 27, CISC Handbook of Steel Construction, where w-uniformly distributed load.
(a) Write the mathematic formulation for the overhanging span (where 0 < x≤ a) using 4th-order
differential equation. A, from the span 0≤x≤1, given in the Beam Diagram, should be used to obtain
the boundary conditions of the overhanging span at x₁-0.
(b) Solve the differential equation for deflection Ax₂ (
HIMI
27. BEAM OVERHANGING ONE SUPPORT-UNIFORMLY DISTRIBUTED LOAD BETWEEN SUPPORTS
Equivalent Tabular Load.
R=V.....
R
M
Mmax
Shear
Moment
Name:
w
AR
LA
M max. (at center)......
M......
JARAY DISA 9915 TA 0204 par
A max. (at center)
A₁
= WI
w!
2
w (1/2-x)
w12
8
WX
(1-x)
MARD OC
5w/4
384 El
wx (13-2/x2 + x³)
24 E
w13x,
24 El
Transcribed Image Text:Student ID: FA(5:30PM) or FB(1:00PM) 1. Beam Diagram 27, CISC Handbook of Steel Construction, where w-uniformly distributed load. (a) Write the mathematic formulation for the overhanging span (where 0 < x≤ a) using 4th-order differential equation. A, from the span 0≤x≤1, given in the Beam Diagram, should be used to obtain the boundary conditions of the overhanging span at x₁-0. (b) Solve the differential equation for deflection Ax₂ ( HIMI 27. BEAM OVERHANGING ONE SUPPORT-UNIFORMLY DISTRIBUTED LOAD BETWEEN SUPPORTS Equivalent Tabular Load. R=V..... R M Mmax Shear Moment Name: w AR LA M max. (at center)...... M...... JARAY DISA 9915 TA 0204 par A max. (at center) A₁ = WI w! 2 w (1/2-x) w12 8 WX (1-x) MARD OC 5w/4 384 El wx (13-2/x2 + x³) 24 E w13x, 24 El
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