Need help with this problem ps Date:Name:1. At time t s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0°above the + axis. As the puck slides, a constant acceleration acts on it that has thefollowing components: ax =-0.360 m/s and ay =-0.980 m/s. What is the velocity ofthe puck at time t 1.50 s?%3DV =2. A spaceship is observed traveling in the positive x direction with a speed of 150 m/swhen it begins accelerating at a constant rate. The spaceship is observed 25 s latertraveling with an instantaneous velocity of 1500 m/s at an angle of 55° above the tx axis.What was the magnitude of the acceleration of the spaceship during the 25 seconds?What was the magnitude of the displacement of the spaceship during the 25 seconds?

Given: The initial velocity of puck is u=3.60 m/s. The angle of puck with the horizontal axis is θ=35.0∘. The horizontal component of acceleration is ax=-0.360 m/s2. The vertical component of acceleration is ay=-0.980 m/s2. The time taken to move is t=1.50 s. The formula to calculate the final velocity along the horizontal axis is, vx=ucosθ+axt Here, vx is the final velocity along horizontal axis, u is the initial velocity, θ is the angle made with the horizontal axis, ax is the component of acceleration along horizontal axis and t is the time taken. Substitute all the known values in the formula to calculate the final velocity along the horizontal axis. vx=3.60 m/scos35.0∘+-0.360 m/s21.50 s=3.60 m/s0.819-0.54 m/s=2.95 m/s-0.54 m/s=2.41 m/sThe formula to calculate the final velocity along the vertical axis is, vy=usinθ+ayt Here, vy is the final velocity along vertical axis and ay is the component of acceleration along vertical axis. Substitute all the known values in the formula to calculate the final velocity along the vertical axis. vy=3.60 m/ssin35.0∘+-0.980 m/s21.50 s=3.60 m/s0.574-1.47 m/s=2.07 m/s-1.47 m/s=0.60 m/s The formula to calculate the final velocity of puck is, v=vx2+vy2 Here, v is the final velocity of puck. Substitute the known values in the formula to calculate the final velocity. v=2.41 m/s2+0.60 m/s2=5.81 m2/s2+0.36 m2/s2=6.17 m2/s2=2.48 m/s Thus, the final velocity of puck at t=1.50 s is 2.48 m/s.

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Advanced Physics

1. At time t G s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0° above the + axis. As the puck slides, a constant acceleration acts on it that has the following components: ax = -0.360 m/s² and ay =-0.980 m/s². What is the velocity of the puck at time t= 1.50 s? %3D %3D

1. At time t G s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0° above the + axis. As the puck slides, a constant acceleration acts on it that has the following components: ax = -0.360 m/s² and ay =-0.980 m/s². What is the velocity of the puck at time t= 1.50 s? %3D %3D