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A small car (800 kg) and a large truck (4000 kg) travel toward each other, each at 8.00 m/s, and have a head-on perfectly inelastic collision. The time duration of the collision is 0.120 seconds. We know intuitively that it is safer to be in the truck, but why? Do the vehicles experience different forces? Do the drivers? Calculate the force exerted on each driver by their seatbelts.

A small car (800 kg) and a large truck (4000 kg) travel toward each other, each at 8.00 m/s, and have a head-on perfectly inelastic collision. The time duration of the collision is 0.120 seconds. We know intuitively that it is safer to be in the truck, but why? Do the vehicles experience different forces? Do the drivers? Calculate the force exerted on each driver by their seatbelts.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I am confused how he go 88 there is no calcualtion 

Example 3 A small car (800 kg) and a large truck (4000 kg) travel toward each other, each at 8.00 m/s, and have a head-on perfectly inelastic collision. The time duration of the collision is 0.120 seconds. We know intuitively that it is safer to be in the truck, but why? Do the vehicles experience different forces? Do the drivers? Calculate the force exerted on each driver by their seatbelts. fmls = 25,600 kmls Ys00 v=25,60. 5,33 m/s (T
Transcribed Image Text:Example 3 A small car (800 kg) and a large truck (4000 kg) travel toward each other, each at 8.00 m/s, and have a head-on perfectly inelastic collision. The time duration of the collision is 0.120 seconds. We know intuitively that it is safer to be in the truck, but why? Do the vehicles experience different forces? Do the drivers? Calculate the force exerted on each driver by their seatbelts. fmls = 25,600 kmls Ys00 v=25,60. 5,33 m/s (T
1 - Fat Ap= AP car p0 (5.33) - (- Fab.s) = 10,667 g.4/1= Fot cow F / ur - 88.9 kN こ こ~&8.9kw
Transcribed Image Text:1 - Fat Ap= AP car p0 (5.33) - (- Fab.s) = 10,667 g.4/1= Fot cow F / ur - 88.9 kN こ こ~&8.9kw
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