1. Assuming general shear failure and using the Terzaghi equation with a FOS of 4 find the allowable gross bearing load the following footing can sustain: 3ft continuous footing set 3ft below grade in a 28deg phi soil with a c' of 400psf and a unit wt of 110psf .

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Chapter2: Loads On Structures
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### Bearing Capacity Calculation Using Terzaghi's Equation

1. **Problem Statement:**
   - **Scenario:** Assume general shear failure.
   - **Task:** Using the Terzaghi equation with a Factor of Safety (FOS) of 4, find the allowable gross bearing load the following footing can sustain.
   - **Footing Details:** A 3 ft continuous footing set 3 ft below grade.
   - **Soil Properties:** 28° phi (friction angle) soil, cohesion (c') of 400 psf, and a unit weight (γ) of 110 psf.

### Calculation Steps:

1. **Terzaghi’s Bearing Capacity Equation:**
\[ q_{ult} = c' N_c + \gamma D_f N_q + 0.5 \gamma B N_\gamma \]

   Where:
   - \( q_{ult} \) = ultimate bearing capacity
   - \( c' \) = cohesion of soil
   - \( γ \) = unit weight of soil
   - \( D_f \) = depth of footing
   - \( B \) = width of continuous footing
   - \( N_c, N_q, N_γ \) = bearing capacity factors dependent on the angle of internal friction (φ)

2. **Bearing Capacity Factors for φ = 28° (approx.):**
   - \( N_c \approx 22.5 \)
   - \( N_q \approx 12.0 \)
   - \( N_γ \approx 15.7 \)

3. **Plugging in the Values:**
\[ q_{ult} = (400 \times 22.5) + (110 \times 3 \times 12.0) + (0.5 \times 110 \times 3 \times 15.7) \]

4. **Calculate Each Term:**
\[ 400 \times 22.5 = 9000 \]
\[ 110 \times 3 \times 12.0 = 3960 \]
\[ 0.5 \times 110 \times 3 \times 15.7 = 2590.5 \]

5. **Sum of Terms:**
\[ q_{ult} = 9000 + 3960 + 2590.5 = 15550.5 \text{ psf} \]

6. **Applying Factor of Safety:**
Transcribed Image Text:### Bearing Capacity Calculation Using Terzaghi's Equation 1. **Problem Statement:** - **Scenario:** Assume general shear failure. - **Task:** Using the Terzaghi equation with a Factor of Safety (FOS) of 4, find the allowable gross bearing load the following footing can sustain. - **Footing Details:** A 3 ft continuous footing set 3 ft below grade. - **Soil Properties:** 28° phi (friction angle) soil, cohesion (c') of 400 psf, and a unit weight (γ) of 110 psf. ### Calculation Steps: 1. **Terzaghi’s Bearing Capacity Equation:** \[ q_{ult} = c' N_c + \gamma D_f N_q + 0.5 \gamma B N_\gamma \] Where: - \( q_{ult} \) = ultimate bearing capacity - \( c' \) = cohesion of soil - \( γ \) = unit weight of soil - \( D_f \) = depth of footing - \( B \) = width of continuous footing - \( N_c, N_q, N_γ \) = bearing capacity factors dependent on the angle of internal friction (φ) 2. **Bearing Capacity Factors for φ = 28° (approx.):** - \( N_c \approx 22.5 \) - \( N_q \approx 12.0 \) - \( N_γ \approx 15.7 \) 3. **Plugging in the Values:** \[ q_{ult} = (400 \times 22.5) + (110 \times 3 \times 12.0) + (0.5 \times 110 \times 3 \times 15.7) \] 4. **Calculate Each Term:** \[ 400 \times 22.5 = 9000 \] \[ 110 \times 3 \times 12.0 = 3960 \] \[ 0.5 \times 110 \times 3 \times 15.7 = 2590.5 \] 5. **Sum of Terms:** \[ q_{ult} = 9000 + 3960 + 2590.5 = 15550.5 \text{ psf} \] 6. **Applying Factor of Safety:**
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