1. An electron having velocity v= -1.2×10* j m/s enters a uniform magnetic field of 2 T as shown in Figure 1. It is deflected downward on the y-z plane and leaves the magnetic field with a velocityv = +1.2×10* j m/s. (i) Determine the radius of curvature of the electron's path and the distance travelled by the electron while in the field. (ii) Calculate the time spent by the electron in the magnetic field. (ii) State the direction of the magnetic field. Explain your answer. (iv) Find the magnetic force in vector form acting on the electron when it has travelled one-quarter of its entire path in the magnetic field. v =-1.2×10 jm/s y v = +1.2×10 į m/s
1. An electron having velocity v= -1.2×10* j m/s enters a uniform magnetic field of 2 T as shown in Figure 1. It is deflected downward on the y-z plane and leaves the magnetic field with a velocityv = +1.2×10* j m/s. (i) Determine the radius of curvature of the electron's path and the distance travelled by the electron while in the field. (ii) Calculate the time spent by the electron in the magnetic field. (ii) State the direction of the magnetic field. Explain your answer. (iv) Find the magnetic force in vector form acting on the electron when it has travelled one-quarter of its entire path in the magnetic field. v =-1.2×10 jm/s y v = +1.2×10 į m/s
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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please help to solve part 4th please
![1. An electron having velocity v= -1.2×10* j m/s enters a uniform magnetic field of 2 T as
shown in Figure 1. It is deflected downward on the y-z plane and leaves the magnetic
field with a velocityv = +1.2×10* j m/s.
(i)
Determine the radius of curvature of the electron's path and the distance travelled
by the electron while in the field.
(ii)
Calculate the time spent by the electron in the magnetic field.
(ii)
State the direction of the magnetic field. Explain your answer.
(iv) Find the magnetic force in vector form acting on the electron when it has travelled
one-quarter of its entire path in the magnetic field.
v =-1.2×10 jm/s
y
v = +1.2×10 į m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2dd4664-aa5f-4f1d-a80b-d4068cd44465%2F23551c1e-b005-4487-82b6-db38b4a9e278%2Fiowq30m_processed.png&w=3840&q=75)
Transcribed Image Text:1. An electron having velocity v= -1.2×10* j m/s enters a uniform magnetic field of 2 T as
shown in Figure 1. It is deflected downward on the y-z plane and leaves the magnetic
field with a velocityv = +1.2×10* j m/s.
(i)
Determine the radius of curvature of the electron's path and the distance travelled
by the electron while in the field.
(ii)
Calculate the time spent by the electron in the magnetic field.
(ii)
State the direction of the magnetic field. Explain your answer.
(iv) Find the magnetic force in vector form acting on the electron when it has travelled
one-quarter of its entire path in the magnetic field.
v =-1.2×10 jm/s
y
v = +1.2×10 į m/s
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