1. (a) Verify that the function y = x³ 2xy + 2y = 8x³ (b) Find a value for c that satisfies the initial condition y(2) = 6. 2. Use separation of variables to solve the following problems dy =-ty, y(0)=1/√ dt y² + 5 y (a) (b) dy dt -, y(0) = -2 dy (c) = 3y(y - 5), y(0) = 8 dt where 3. Consider the following very simple model of blood cholesterol levels based on the fact that cholesterol is manufactured by the body for use in the construction of cell walls and is absorbed from foods containing cholesterol: Let C(t) be the amount (in milligrams per deciliter) of cholesterol in the blood of a particular person at time t (in days). Then is a solution to the differential equation dC dt = k₁(NC) + k₂E N = person's natural cholesterol level k₁ production parameter E k₂ daily rate at which cholesterol is eaten absorption parameter (a) Suppose N = 200, k₁= 0.1, k₂ = 0.1, E = 400, and C(0) = 150. What will the person's cholesterol level be after 2 days on this diet? (Hint: solve the ODE, then plug in t = 2) (b) With the initial conditions as above, what will the person's cholesterol level be after 5 days on this diet? (c) What will the person's cholesterol level be after a long time on this diet? (d) High levels of cholesterol in the blood are known to be a risk factor for heart disease. Suppose that, after a long time on the high cholesterol diet described above, the person goes on a very low cholesterol diet, so E changes to E = 100. (The initial cholesterol level at the starting time of this diet is the result of part (c).) What will the person's cholesterol level be after 1 day on the new diet, after 5 days on the new diet, and after a very long time on the new diet? 1
1. (a) Verify that the function y = x³ 2xy + 2y = 8x³ (b) Find a value for c that satisfies the initial condition y(2) = 6. 2. Use separation of variables to solve the following problems dy =-ty, y(0)=1/√ dt y² + 5 y (a) (b) dy dt -, y(0) = -2 dy (c) = 3y(y - 5), y(0) = 8 dt where 3. Consider the following very simple model of blood cholesterol levels based on the fact that cholesterol is manufactured by the body for use in the construction of cell walls and is absorbed from foods containing cholesterol: Let C(t) be the amount (in milligrams per deciliter) of cholesterol in the blood of a particular person at time t (in days). Then is a solution to the differential equation dC dt = k₁(NC) + k₂E N = person's natural cholesterol level k₁ production parameter E k₂ daily rate at which cholesterol is eaten absorption parameter (a) Suppose N = 200, k₁= 0.1, k₂ = 0.1, E = 400, and C(0) = 150. What will the person's cholesterol level be after 2 days on this diet? (Hint: solve the ODE, then plug in t = 2) (b) With the initial conditions as above, what will the person's cholesterol level be after 5 days on this diet? (c) What will the person's cholesterol level be after a long time on this diet? (d) High levels of cholesterol in the blood are known to be a risk factor for heart disease. Suppose that, after a long time on the high cholesterol diet described above, the person goes on a very low cholesterol diet, so E changes to E = 100. (The initial cholesterol level at the starting time of this diet is the result of part (c).) What will the person's cholesterol level be after 1 day on the new diet, after 5 days on the new diet, and after a very long time on the new diet? 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:1. (a) Verify that the function y = x³ is a solution to the differential equation
2xy + 2y = 8x³
(b) Find a value for c that satisfies the initial condition y(2) = 6.
2. Use separation of variables to solve the following problems
dy
=1/√√√T
dt
y(0) = -2
(a)
(b)
(c)
dy y² +5
dt
Y
3y(y-5), y(0) = 8
dy
dt
= -ty, y(0) =
where
=
3. Consider the following very simple model of blood cholesterol levels based on the fact
that cholesterol is manufactured by the body for use in the construction of cell walls and
is absorbed from foods containing cholesterol: Let C(t) be the amount (in milligrams
per deciliter) of cholesterol in the blood of a particular person at time t (in days). Then
dC
dt
= k₁(N − C) + k₂E
N = person's natural cholesterol level.
k₁= production parameter
E = daily rate at which cholesterol is eaten
k₂ absorption parameter
(a) Suppose N = 200, k₁ = 0.1, k₂ = 0.1, E = 400, and C(0) = 150. What will the
person's cholesterol level be after 2 days on this diet? (Hint: solve the ODE, then
plug in t = 2)
(b) With the initial conditions as above, what will the person's cholesterol level be
after 5 days on this diet?
(c) What will the person's cholesterol level be after a long time on this diet?
(d) High levels of cholesterol in the blood are known to be a risk factor for heart
disease. Suppose that, after a long time on the high cholesterol diet described
above, the person goes on a very low cholesterol diet, so E changes to E = 100.
(The initial cholesterol level at the starting time of this diet is the result of part
(c).) What will the person's cholesterol level be after 1 day on the new diet, after
5 days on the new diet, and after a very long time on the new diet?
1

Transcribed Image Text:(e) Suppose the person stays on the high cholesterol diet but takes drugs that block
some of the uptake of cholesterol from food, so k2 changes to k₂ = 0.075. With
the cholesterol level from part (c), what will the person's cholesterol level be after
1 day, after 5 days, and after a very long time?
4. Mobile telephone service has increased rapidly in America since the mid 1990s. Today
almost all residents have cellular service. The follow table shows the percentage of
Americans with cellular service for years 1995 and 2012. Let t represent time in years
starting with t = 0 for the year 1995. Let P represent the corresponding percentage of
residents with cellular service.
Year Americans with cellular service (%)
1995
1996
1997
1998
1999
2000
2001
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
2012
12.69
16.35
20.29
25.08
30.81
38.75
45.00
49.16
55.15
62.85
68.63
76.64
82.47
85.68
89.14
91.86
95.28
98.17
(a) Use exponential growth to fit a model to this data. Show your work for finding
the growth rate k.
(b) Use logistic growth to fit a model to this data. Show your work and justify how
you estimate the carrying capacity and growth rate. Adjust the logistic model
starting at your initial estimates for k and N to get a better fit to the data.
(c) Use Excel to generate a graph with four lines for the data, exponential growth
model, logistic growth model, and adjusted logistic model.
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