3. By finding a suitable integrating factor, solve the following equations: (a) (1−x^2)y′+2xy=(1−x^2)^3/2 (b) y′−ycotx+cosecx=0 (c) (x + y^3)y′ = y (treat y as the independent variable).
3. By finding a suitable integrating factor, solve the following equations: (a) (1−x^2)y′+2xy=(1−x^2)^3/2 (b) y′−ycotx+cosecx=0 (c) (x + y^3)y′ = y (treat y as the independent variable).
3. By finding a suitable integrating factor, solve the following equations: (a) (1−x^2)y′+2xy=(1−x^2)^3/2 (b) y′−ycotx+cosecx=0 (c) (x + y^3)y′ = y (treat y as the independent variable).
3. By finding a suitable integrating factor, solve the following equations: (a) (1−x^2)y′+2xy=(1−x^2)^3/2
(b) y′−ycotx+cosecx=0
(c) (x + y^3)y′ = y (treat y as the independent variable).
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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