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1. А — В: (A, {NA}KAB) 2. В > А: ((Na+1, Na)}KАв 3. А -> В: {Ng+1}KAB 4. B → A: {(K'AB, NA)}KAB Which of the following mutations to messages of the protocol above, would constitute a harmful attack: а) 1. А > В: (C, {NA}KAB) b) 1. А > В: ({NAJKAB, A) с) 4. В > А: (КАв, NA))КАВ d) 4. B → A: {(K'AB, Ng+1)}KaB e) 3. А > В: (Na+1)Кpыв f) 2. В > А: {(NA+1, NA)}KAB Explain your answer below:

1. А — В: (A, {NA}KAB) 2. В > А: ((Na+1, Na)}KАв 3. А -> В: {Ng+1}KAB 4. B → A: {(K'AB, NA)}KAB Which of the following mutations to messages of the protocol above, would constitute a harmful attack: а) 1. А > В: (C, {NA}KAB) b) 1. А > В: ({NAJKAB, A) с) 4. В > А: (КАв, NA))КАВ d) 4. B → A: {(K'AB, Ng+1)}KaB e) 3. А > В: (Na+1)Кpыв f) 2. В > А: {(NA+1, NA)}KAB Explain your answer below:

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Mutation and Type-Flaw Attacks

Consider the following 4-message protocol between A and B, where (N+1) represents the increment

of N:

 

1. А — В: (A, {NA}KAB) 2. В > А: {(Na+1, N8)}KAB 3. А > В: {Na+1}KAB 4. В > А: {(K'AB, NA)}KAB Which of the following mutations to messages of the protocol above, would constitute a harmful attack: a) 1. А > В: (C, {Na}KAB) b) 1. A → B: ({Na}KAB, A) с) 4. В > А: {(KAB, NA)}KAB d) 4. В > А: {(K'aB, Ng+1)}KAB e) 3. А -> В: {Ng+1}KpbB f) 2. В > А: {(Na+1, NA)}KAB Explain your answer below:
Transcribed Image Text:1. А — В: (A, {NA}KAB) 2. В > А: {(Na+1, N8)}KAB 3. А > В: {Na+1}KAB 4. В > А: {(K'AB, NA)}KAB Which of the following mutations to messages of the protocol above, would constitute a harmful attack: a) 1. А > В: (C, {Na}KAB) b) 1. A → B: ({Na}KAB, A) с) 4. В > А: {(KAB, NA)}KAB d) 4. В > А: {(K'aB, Ng+1)}KAB e) 3. А -> В: {Ng+1}KpbB f) 2. В > А: {(Na+1, NA)}KAB Explain your answer below:
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