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1. A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.20 m above. The second student catches the keys 2.20 s later. a. With what initial velocity (magnitude and direction) were the keys thrown? b. What was the velocity (magnitude and direction) of the keys just before they were caught?

1. A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.20 m above. The second student catches the keys 2.20 s later. a. With what initial velocity (magnitude and direction) were the keys thrown? b. What was the velocity (magnitude and direction) of the keys just before they were caught?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.20 m above. The second student catches the keys 2.20 s later. a. With what initial velocity (magnitude and direction) were the keys thrown? b. What was the velocity (magnitude and direction) of the keys just before they were caught?
Transcribed Image Text:1. A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.20 m above. The second student catches the keys 2.20 s later. a. With what initial velocity (magnitude and direction) were the keys thrown? b. What was the velocity (magnitude and direction) of the keys just before they were caught?
Kinematics: Vx = Vxo + axt (x – xo) = vxot +;axt? vž – vžo = 2a,(x – xo) Vy = Vyo + Ayt (y – yo) = vyot +ayt? vž – vžo = 2a,(y – yo) 1 %3D 7 = xî + yĵ di う= Vzî + vyĵ dt axî + ayĵ dt E = = m dt di (constant mass) dt EF = må, (constant mass) Kinetic Friction Force: fk = HxN Static Friction Force: fs < HsN g = 9.80 m/s²
Transcribed Image Text:Kinematics: Vx = Vxo + axt (x – xo) = vxot +;axt? vž – vžo = 2a,(x – xo) Vy = Vyo + Ayt (y – yo) = vyot +ayt? vž – vžo = 2a,(y – yo) 1 %3D 7 = xî + yĵ di う= Vzî + vyĵ dt axî + ayĵ dt E = = m dt di (constant mass) dt EF = må, (constant mass) Kinetic Friction Force: fk = HxN Static Friction Force: fs < HsN g = 9.80 m/s²
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