1. A researcher has developed a new test of self-esteem. To evaluate the reliability of the test, the researcherobtains a sample of n = 8 participants. Each individual takes the test on a Monday morning, then returns twoweeks later to take the test again. The two scores for each individual are reported in the following table.First Test11Second Test137121211141010129.81314M2nd = 11s? = 10.00Mist = 10.25s? = 3.64s = 1.91s = 3.16a. Compute the Pearson correlationb. If you were trying to predict a value of the Second Test score from a value of the First Test score,what would the equation be?c. If someone had a score of 15 for the First Test, what would the best estimate of their Y score be?

(a) Use EXCEL to obtain the value correlation coefficient r: EXCEL procedure: Go to EXCEL Go…

Answered: 1. A researcher has developed a new…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A repeated-measures experiment and a matched-subjects experiment each produce a t-statistic with df = 13. How many individuals participated in each study? 14 for repeated and 28 for matched. 14 for repeated and 14 for matched. 14 for repeated and 15 for matched. 14 for repeated and 15 for matched.
(a) Find the test statistic. (b) Find the standardized test statistic.
n below relates to five brands of tires chosen at random from local stores. Six tires of each brand and placed in random order on a machine that tested tread durability in thousands of miles. the durability measurements are different for different brands at 10% level of significance. Click this button to reveal the data Brand Durability Measure 1 55 1 56 1 59 1 55 1 60 1 57 39 42 43 41 41 222 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 5 5 5 5 5 5 Download CSV file 2 39 41 3 40 45454442 42 43 43 43 39 40 43 46 42 45 42 42 44
Now that we have the observed and expected frequencies, the other components for the test statistic can be found. The following table gives the given observed data and the calculated expected frequencies. The sum of all the values in the final column will be the x test statistic. Complete the table, rounding values in the final column to four decimal places and x to three decimal places. Squared Difference Squared Difference Divided by Expected Frequency Observed Expected Frequency Hours Difference Age Group of Frequency fij fj - eij (fij – e;)² Sleep eij eij 6.1504 Fewer 39 or 38 – 35.52 2.482 = - %3D 38 35.52 35.52 0.1732 than 6 younger 2.48 6.1504 Fewer 40 or 36 38.48 -2.48 6.1504 than 6 older 6 to 39 or 60 56.16 14.7456 0.2626 6.9 younger 6 to 40 or 57 60.84 -3.84 0.2424 6.9 older 7 to 39 or 76 72 4.00 16.0000 7.9 younger 7 to 40 or 74 78 -4.00 16.0000 7.9 older 8 or 39 or 66 76.32 106.5024 1.3955 more younger 8 or 40 or 93 82.68 10.32 106.5024 more older x? = EE i (fj – ej)2 eij…
The study from the previousquestion was repeated with thenew data shown to the right.Compute the test statistic: (Round to two decimal places asneeded.)
Male Female 60 A factory hiring people to work on an assembly line gives job applicants a test of manual agility. This test counts how many strangely shaped pegs the applicant can fit into matching holes in a one-minute period. The table to the right summaries the data Pegs placed: by gender of the job applicant. Assume that all conditions necessary for inference are met. Complete parts a through f. Number of subjects 60 Mean SD 19.66 18.29 2.81 3.92 a) Find 95% confidence intervals for the average number of pegs that males and females can each place. The 95% confidence interval for males is (Round to two decimal places as needed.)
A chemist measures the haptoglobin concentrations (in grams per liter) in the blood of eight healthy adults. Following are the values: 1.82 3.32 1.07 1.27 0.49 3.79 0.15 1.98 At the 2% significance level, test the claim that the mean haptoglobin concentration in adults is less than two grams per liter. What type of error could you have made in your decision?
8.3 Inference for Quantitative Variable: Comparing Two Means Pulse Rates Mr. Wilcox's class performed an experiment to investigate whether drinking a caffeinated beverage would increase pulse rates. Twenty students in the class volunteered to take part in the experiment. All of the students measured their initial pulse rates (in beats per minute). Then Mr. Wilcox randomly assigned the students into two groups of 10. Each student in the first group drank 12 ounces of cola with caffeine. Each student in the second group drank 12 ounces of caffeine-free cola. All students then measured their pulse rates again. The table displays the change in pulse rate for the students in both groups. Construct and interpret a 95% confidence interval for the difference in true mean change in pulse rate for subjects like these who drink caffeine versus who drink no caffeine. Change in pulse rate (Final pulse rate - Initial pulse rate) 5 6 1 4 4 1 2 -1 Caffeine 8 No caffeine 3 3 -2 1 -1 STATE the parameter…
You read a newspaper article that says that 74% of households in your town participate in a recycling program. To test that statement at the 10% significance level, you randomly select 54 households in town and you find that 35 of them participate in the recycling program. Ho: P=0.74 Ha:P=/ 0.74 Find the P-value. Round your answer to 3 decimal places.
A score that is 2 points higher than the sample mean has a z-score of z = 0.5 and a score of X = 44 has a z-score of -1.00What is the sample mean?
NEW STUDY: A researcher is interested in the relationship between levels of stress at work and self-reports of overall health. Stress at work is measured on a scale from 0 (no stress at work) to 100 (extreme levels of stress at work). The researcher conducts a study with 11 subjects and determines that the relationship between self-reports of stress and self-reports of overall heath is r = -.41. Which test was conducted for this study? Group of answer choices z-test t-test correlation chi-square
Lecture(8.4): Researchers were interested in whether the number of books children carried differed between gender. It was hypothesized that girls would carry more books than boys.Twenty children were recruited and matched based on age and SES..Researchers then collected the number of the age of the appropiate books the children carried. A Summary of the result is given below: Girls 15 7 22 13 26 14 12 11 18 30 Boys 12 10 16 8 17 9 15 10 20 15 Test the hypotheses at (alpha=0.05) level of signifance

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