1. (a) Matrix A is 5 by 8 and its rank is 3. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.? (b) ) Matrix A is 7 by 9 and its rank is 4. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.?

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### Linear Algebra Problem Set

#### Question 1

1. (a) Matrix A is 5 by 8 and its rank is 3. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.?
   
   (b) Matrix A is 7 by 9 and its rank is 4. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.?

---

### Explanation

For each part of this question, you will need to consider the properties and implications of the given matrices.

#### Part (a)

**Matrix A Details:**
- Dimensions: 5 rows by 8 columns
- Rank: 3

When examining the subspaces and related questions:
- **Column Space:** The dimension of the column space (also known as the rank) is 3. This implies that there are 3 linearly independent columns.
- **Null Space:** The nullity, which is the dimension of the null space, can be calculated using the formula: nullity = number of columns - rank. Therefore, the nullity in this case is 8 - 3 = 5.
- **Row Space:** The row space has the same dimension as the rank, which is 3.
- **Left Null Space:** The dimension of the left null space is given by: number of rows - rank. Thus, it is 5 - 3 = 2.

Regarding the solutions to Ax = b:
- **Existence of Solutions:** A general solution requires the right-hand side vector b to lie within the column space of matrix A. Given that the rank is 3 and there are 5 rows, solutions exist if rank(A) = rank([A|b]).
- **Number of Solutions:** If solutions exist, because the null space dimension is 5, there will be infinitely many solutions with a 5-dimensional solution space.

#### Part (b)

**Matrix A Details:**
- Dimensions: 7 rows by 9 columns
- Rank: 4

Evaluating subspaces and related questions:
- **Column Space:** The rank of 4 indicates that the column space has a dimension of 4, implying 4 linearly independent columns.
- **Null Space:** The dimension of the null space is 9 - 4 = 5, as there are 9 columns and the rank is 4
Transcribed Image Text:### Linear Algebra Problem Set #### Question 1 1. (a) Matrix A is 5 by 8 and its rank is 3. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.? (b) Matrix A is 7 by 9 and its rank is 4. What can you say about the four subspaces, their dimensions, the number of solutions to Ax = b, etc.? --- ### Explanation For each part of this question, you will need to consider the properties and implications of the given matrices. #### Part (a) **Matrix A Details:** - Dimensions: 5 rows by 8 columns - Rank: 3 When examining the subspaces and related questions: - **Column Space:** The dimension of the column space (also known as the rank) is 3. This implies that there are 3 linearly independent columns. - **Null Space:** The nullity, which is the dimension of the null space, can be calculated using the formula: nullity = number of columns - rank. Therefore, the nullity in this case is 8 - 3 = 5. - **Row Space:** The row space has the same dimension as the rank, which is 3. - **Left Null Space:** The dimension of the left null space is given by: number of rows - rank. Thus, it is 5 - 3 = 2. Regarding the solutions to Ax = b: - **Existence of Solutions:** A general solution requires the right-hand side vector b to lie within the column space of matrix A. Given that the rank is 3 and there are 5 rows, solutions exist if rank(A) = rank([A|b]). - **Number of Solutions:** If solutions exist, because the null space dimension is 5, there will be infinitely many solutions with a 5-dimensional solution space. #### Part (b) **Matrix A Details:** - Dimensions: 7 rows by 9 columns - Rank: 4 Evaluating subspaces and related questions: - **Column Space:** The rank of 4 indicates that the column space has a dimension of 4, implying 4 linearly independent columns. - **Null Space:** The dimension of the null space is 9 - 4 = 5, as there are 9 columns and the rank is 4
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