1. A gas within a piston-cylinder assembly undergoes a thermodynamic cycle consisting of three processes: Process 1-2: Compression with PV = constant, from P₁ = 1 bar, V₁ = 2 m³ to V₂ = 0.2 m³, U₂ - U₁ = 100 kJ; Process 2-3: Constant volume to P3 = P₁; Process 3-1: Constant-pressure and adiabatic process. Neglect the changes of kinetic and potential energy in all three processes. (a) Sketch the cycle on a P-V diagram; (b) Determine the net work (i.e., W₁2+ W23+ W31) of the cycle, in kJ; (c) Determine the heat transfer for process 2-3, in kJ. Hint: System's state variables remain unchanged after a cycle, i.e. (U₂− U₁) + (U3-U₂) + (U₁-U3) = 0

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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1.
A gas within a piston-cylinder assembly undergoes a thermodynamic cycle consisting of three processes:
Process 1-2: Compression with PV = constant, from P₁ = 1 bar, V₁ = 2 m³ to V₂ = 0.2 m³, U₂ − U₁ = 100 kJ;
2
Process 2-3: Constant volume to P3 = P₁;
Process 3-1: Constant-pressure and adiabatic process.
Neglect the changes of kinetic and potential energy in all three processes.
(a) Sketch the cycle on a P-V diagram;
(b) Determine the net work (i.e., W12 + W23 + W31) of the cycle, in kJ;
(c) Determine the heat transfer for process 2-3, in kJ.
Hint: System's state variables remain unchanged after a cycle, i.e. (U₂ − U₁) + (U3 − U₂) + (U₁ − U3) = 0
Transcribed Image Text:1. A gas within a piston-cylinder assembly undergoes a thermodynamic cycle consisting of three processes: Process 1-2: Compression with PV = constant, from P₁ = 1 bar, V₁ = 2 m³ to V₂ = 0.2 m³, U₂ − U₁ = 100 kJ; 2 Process 2-3: Constant volume to P3 = P₁; Process 3-1: Constant-pressure and adiabatic process. Neglect the changes of kinetic and potential energy in all three processes. (a) Sketch the cycle on a P-V diagram; (b) Determine the net work (i.e., W12 + W23 + W31) of the cycle, in kJ; (c) Determine the heat transfer for process 2-3, in kJ. Hint: System's state variables remain unchanged after a cycle, i.e. (U₂ − U₁) + (U3 − U₂) + (U₁ − U3) = 0
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