1.) A gas at 250 K and 1520 kPa has a molar volume 12% smaller than that calculated from the perfect gas law. Calculate (a) the compression factor under these conditions, and (b) the molar volume of the gas. Answer: [0.88; 1.20] 2.) At 300 K and 2026 kPa, the compressibility factor of a gas is 0.86. Calculate the volume occupied by 8.2 mmol of the gas under these conditions. Answer: [8.68 x 10^-3]
1.) A gas at 250 K and 1520 kPa has a molar volume 12% smaller than that calculated from the perfect gas law. Calculate (a) the compression factor under these conditions, and (b) the molar volume of the gas. Answer: [0.88; 1.20] 2.) At 300 K and 2026 kPa, the compressibility factor of a gas is 0.86. Calculate the volume occupied by 8.2 mmol of the gas under these conditions. Answer: [8.68 x 10^-3]
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.43QP: A McLeod gauge measures low gas pressures by compressing a known volume of the gas at constant...
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1.) A gas at 250 K and 1520 kPa has a molar volume 12% smaller than that calculated from the
perfect
volume of the gas. Answer: [0.88; 1.20]
2.) At 300 K and 2026 kPa, the compressibility factor of a gas is 0.86. Calculate the volume occupied
by 8.2 mmol of the gas under these conditions. Answer: [8.68 x 10^-3]
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