1. A curve has the equation y=x³+8x²+5x. dy (i) Work out the coordinates of the two turning points. = 3x²+16x+5 dy dx о = 3x² + 16x +5 0 = (3x+1)(x+5) 3x+1=0 - x+5=0 *= -1 1= (-13)³ +8 (½3)² + 5 (-1/3) = - 22/27 (-1/3-22/27) y= (-5)³ +8 (-5)² + 5(-5) = 50 (-5.50) -ㅎ -22 -5 50 ) and ( -0.333-0.815 (................
1. A curve has the equation y=x³+8x²+5x. dy (i) Work out the coordinates of the two turning points. = 3x²+16x+5 dy dx о = 3x² + 16x +5 0 = (3x+1)(x+5) 3x+1=0 - x+5=0 *= -1 1= (-13)³ +8 (½3)² + 5 (-1/3) = - 22/27 (-1/3-22/27) y= (-5)³ +8 (-5)² + 5(-5) = 50 (-5.50) -ㅎ -22 -5 50 ) and ( -0.333-0.815 (................
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.1: Lines
Problem 4ECP: Find the distance between the point 3,2 and the line 3x+5y=2.
Related questions
Question
![1. A curve has the equation y=x³+8x²+5x.
dy
(i) Work out the coordinates of the two turning points.
=
3x²+16x+5
dy
dx
о
= 3x² + 16x +5
0 = (3x+1)(x+5)
3x+1=0
-
x+5=0
*= -1
1= (-13)³ +8 (½3)² + 5 (-1/3) = - 22/27
(-1/3-22/27)
y= (-5)³ +8 (-5)² + 5(-5) = 50
(-5.50)
-ㅎ
-22
-5
50
) and (
-0.333-0.815
(................](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe68930b7-6552-46b3-ab6f-1ff15a13eb9f%2Fb68ab492-700d-4bd9-9878-3ee6e5e65382%2F66ns4jp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A curve has the equation y=x³+8x²+5x.
dy
(i) Work out the coordinates of the two turning points.
=
3x²+16x+5
dy
dx
о
= 3x² + 16x +5
0 = (3x+1)(x+5)
3x+1=0
-
x+5=0
*= -1
1= (-13)³ +8 (½3)² + 5 (-1/3) = - 22/27
(-1/3-22/27)
y= (-5)³ +8 (-5)² + 5(-5) = 50
(-5.50)
-ㅎ
-22
-5
50
) and (
-0.333-0.815
(................
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