1. A chemistry instructor decides to change his students' grades, using a 6th root grading curve. This works as follows: if the initial grade is 0 < x < 100, then the grade after the curving will be f(x) = 100 · 100 2 46.4 · xổ. (a) Find the standard linear approximation of f at x = 64. You may use f(x) 46.4 · xổ to calculate this linear approximation. (b) John has a 62 in the class prior to the curve. Using part a), give an approximation of John's grade after applying the grading curve (do not explicitly calculate f(62)).
1. A chemistry instructor decides to change his students' grades, using a 6th root grading curve. This works as follows: if the initial grade is 0 < x < 100, then the grade after the curving will be f(x) = 100 · 100 2 46.4 · xổ. (a) Find the standard linear approximation of f at x = 64. You may use f(x) 46.4 · xổ to calculate this linear approximation. (b) John has a 62 in the class prior to the curve. Using part a), give an approximation of John's grade after applying the grading curve (do not explicitly calculate f(62)).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1. A chemistry instructor decides to change his students' grades, using a 6th root grading
curve. This works as follows: if the initial grade is 0 < x < 100, then the grade after
the curving will be
6
f (x) = 100 ·
100
2 46.4 · xồ.
(a) Find the standard linear approximation of f at x = 64. You may use f(x)
46.4 · xề to calculate this linear approximation.
(b) John has a 62 in the class prior to the curve. Using part a), give an approximation
of John's grade after applying the grading curve (do not explicitly calculate f(62)).
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